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2 years ago

There are 181 students going on a college field trip.

Mathematics

1 answer:

Norma-Jean [14]2 years ago

3 0

Answer:

42.5 (students that are on each bus)

Step-by-step explanation:

181 (students)-11 (students in cars) =170 students left

170(students left)÷4(buses)= 42.5(students that are on each bus)

Hope this help you

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What is the answer for 12

LenaWriter [7]

Answer:

12 = 12

Step-by-step explanation: equal integer theorem.

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3 years ago

(15 points)Please help out if you can!

Levart [38]

Answer:

The maximum is -3

Step-by-step explanation:

A parabola that opens down (- in front), the vertex represents the highest point on the graph, or the maximum value.

The vertex of the equation is (-7,-3)

So, the maximum y value is -3

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2 years ago

There are 12 white shirts,8 blue shirts,and 6 red shirts on a rack.Which colors have a ratio of 3:4

saw5 [17]

The 12 white shirts because if u times 3:4 that is the answer

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3 years ago

Read 2 more answers

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

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2 years ago

Evaluate<br> expression 4+5.23 + 3 =

zvonat [6]

Answer:

12.23

Step-by-step explanation:

4+5.23 = 9.23

9.23 + 3 = 12.23

5 0

2 years ago