All categories

3 years ago

The scores of 4th and 5th graders on a test about polygons and their characteristics are summarized below

Mathematics

1 answer:

nlexa [21]3 years ago

3 0

Answer: Part A: In which grade did the students do the best? Answer; 4th grade, they have a higher median of 68

Part B: what best describes the shape of the two graphs? Answer: 5th grade is roughly symmetrical without letters in fourth grade is skewed right

Step-by-step explanation: That’s for the answers for the 3rd question on Topic 4 of Section 9. Hope that helped:))

You might be interested in

G−9=−19 What does g=???

Free_Kalibri [48]

Answer:

g=-19+9

g=-10

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Abby's score in a

mezya [45]

Answer: 5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the answer of reciprocal of 1/7

serg [7]

7/1, I think that’s right

3 0

3 years ago

Read 2 more answers

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---Approximated

7 0

3 years ago

Consider the following statement: The sum of two numbers is always greater than the larger number. Which of the following is tru

g100num [7]

Answer:

C because you are multiplying. Since you can do zero multiplied zero to get zero, therefore, zero has not changed as the bigger number.

4 0

3 years ago

Read 2 more answers