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uranmaximum [27]
2 years ago
14

Need help find the value of x and y​

Mathematics
1 answer:
Gnoma [55]2 years ago
4 0
<h2><em><u>V</u></em><em><u>A</u></em><em><u>L</u></em><em><u>U</u></em><em><u>E</u></em><em><u> </u></em><em><u> </u></em><em><u>O</u></em><em><u>F</u></em><em><u> </u></em><em><u>X</u></em><em><u>=</u></em><em><u>5</u></em><em><u>0</u></em><em><u> </u></em><em><u>D</u></em><em><u>E</u></em><em><u>G</u></em><em><u>R</u></em><em><u>E</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>N</u></em><em><u>D</u></em><em><u> </u></em><em><u>V</u></em><em><u>A</u></em><em><u>L</u></em><em><u>U</u></em><em><u>E</u></em><em><u> </u></em><em><u>O</u></em><em><u>F</u></em><em><u> </u></em><em><u>Y</u></em><em><u>=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>D</u></em><em><u>E</u></em><em><u>G</u></em><em><u>R</u></em><em><u>E</u></em><em><u>E</u></em></h2>
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Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
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