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3 years ago

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Mathematics

1 answer:

melomori [17]3 years ago

7 0

Answer:

5) 2(4 - n) = -3n

2 × 4 - 2 × n = -3n

8 - 2n = -3n

-2n + 3n = -8

1n = -8

n = -8/1

n = -8

6) 5 - 3(2 + 2w) = -7

5 - 3 × 2 + -3 × 2w = -7

5 - 6 - 6w = -7

-1 - 6w = -7

-6w = -7 + 1

-6w = -6

w = -6/-6

w = 1

7) 5(2r + 3) - 5 = 0

5 × 2r + 5 × 3 - 5 = 0

10r + 15 - 5 = 0

10r + 10 = 0

10r = -10

r = -10/10

r = -1

8) 3 - 5(2d - 3) = 4

3 - 5 × 2d - 5 × -3 = 4

3 - 10d + 15 = 4

-10d + 15 + 3 = 4

-10d + 18 = 4

-10d = 4 - 18

-10d = -14

d = -14/-10

d = 7/5

hope this helps you!!

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<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

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We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

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= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

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Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

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