C the property for this states that the order may change but the the answer will remain the same
Let p be the probability of success, p = 0.4.
Pr[2 success] = nC2 * p^2 * (1-p)^3 = 0.346
Pr[3 success] = nC3 * p^3 * (1-p)^2 = 0.230
Pr[4 success] = nC4 * p^4 * (1-p)^1 = 0.077
So, the probability of getting 2, 3, or 4 success, would be 0.356 + 0.230 + 0.077 = 0.663, alternatively, 66.3%.
Answer:

Step-by-step explanation:
Here, given:

Now, here to find the values of 
As we know: 
Now, substituting x = 4 in f(x):

Now, substituting x = 1/2 in g(x):
