Question

The distance (d) in miles that Cecil runs depends on the number of track practices (p) he attends. D = 2p + 3 i) Solvetheequation d=2p+3forp. ii) How many practices he has to attended to run 13 miles?

Answer 1

Answer: i) $p=\dfrac{d-3}{2}$

ii) He has to attend 5 practices to run 13 miles.

Step-by-step explanation:

Given: The distance (d) in miles that Cecil runs depends on the number of track practices (p) he attends.

$d=2p+3$

i) To solve for p . first subtract 3 from both sides , we get

$d-3=2p$

Divide both sides by 2

$\dfrac{d-3}{2}=p$

So. $p=\dfrac{d-3}{2}$

ii) Put d= 13 , we get

$p=\dfrac{13-3}{2}=\dfrac{10}{2}=5$

i.e. he has to attend 5 practices to run 13 miles.