The answer is B.<span>equally in all directions.
</span>
Answer:
When there are 5 molecules of fructose on each side of the membrane.
Explanation:
The solution will reach equilibrium fro fructose when there are 5 molecules of fructose on each side of the membrane.
A membranous system is said to be at equilibrium when there are equal concentration of a particular molecule on both sides of the membrane.
<em>Hence, for a membranous system with 10 molecules of fructose on one side, an equilibrium can only be reached for fructose when there are 5 molecules on one side and the remaining 5 molecules on the other side. </em>
Answer:
C. only glycolysis and the Krebs cycle
Explanation:
Conversion of 1,3-bisphosphoglycerate into 3-phosphoglycerate and conversion of phosphoenolpyruvate into pyruvate during glycolysis obtains a total of 4 ATP molecules per glucose (2 from each reaction). Here, ATP formation occurs by the transfer of the phosphoryl group from a substrate such as 1,3-bisphosphoglycerate. Therefore, it is called a substrate-level phosphorylation.
Similarly, oxidative decarboxylation of alpha-ketoglutarate into succinyl CoA and conversion of succinyl CoA into succinate forms 2 ATP molecules per glucose during Kreb's cycle. Here, the energy for ATP synthesis is provided by oxidative decarboxylation of a substrate. Therefore, it is also substrate-level phosphorylation.
Answer:
The correct option is : B. Acids and bases will neutralize each other.
Explanation:
Acid is a proton donor and electron-pair acceptor. Whereas, a base is a hydroxide ion donor and electron-pair donor.
The addition of an acid or a base can affect the pH of a solution. Acids lower the pH of a solution, whereas bases increase the pH of a solution.
The pH of an acidic solution < 7 and pH of a basic solution > 7.
When equal amounts of acid and base is mixed together, the solution gets neutralized. This is known as Neutralization reaction. The pH of such a solution is neutral (pH= 7).
