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kipiarov [429]
3 years ago
9

Can anyone help !! Please

Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

the first question is x=68/3 in standard from it is 3x=68

the second question is x= - 11/10

Step-by-step explanation:

for the second question the negative is beside the fraction.

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On a coordinate plane, point A is at (3, 3) and point B is at (negative 3, 3). Point B is the image of point A when A is rotated
Vladimir [108]

Answer:

Point B must be at the same distance from the the origin as point A.

Step-by-step explanation:

Coordinates of point A = (3, 3)

When point A is rotated 90° counterclockwise around the origin, coordinates of the new point B will be (-3, 3)

Distance from origin to point A = \sqrt{(3)^{2}+(3)^2}=3\sqrt{2}

Similarly, distance of point B from the origin = \sqrt{(3)^{2}+(3)^2}=3\sqrt{2}

Therefore, distances of both the points from the origin are same.

Point B must be at the same distance from the the origin as point A.

7 0
3 years ago
Ab+ac-a²-bc ??????????????????​
babunello [35]
Answer: ab+a-b
ab+ac-a2
CLT( collect like terms)
ab+a2+ac-bc
ab+a-b.

Hope this is correct



6 0
3 years ago
4x + 1/3 y 2 what is the value of the expression above when x = 2 and y = 3
GenaCL600 [577]
Hoi!

To solve this, first plug in the values for x and y.

x = 2, so anywhere you see x, put 2 in its place.

y = 3, so anywhere you see y, put 3 in its place.

4(2) +  \frac{1}{2}(3)

4 × 2 = 8

\frac{1}{2} × 3 = 1 \frac{1}{2}


8 +1 \frac{1}{2} = 9 \frac{1}{2}

9 \frac{1}{2} is your answer.



4 0
3 years ago
Read 2 more answers
Can someone please help me with these math problems ASAP?!<br> Thanks in advance! ;)
Mamont248 [21]

Answer:

11) Here given Function,

f(x) = \sqrt{2x-11}

And, g(x) = -|0.1|x+5

For f(x) = g(x)

\sqrt{2x-11}=-|0.1|x+5

2x-11=(-|0.1|x+5)^2

2x-11=0.01x^2 - 10|0.1|x+25

2x=0.01x^2 - 10|0.1|x+25+11

2x=0.01x^2 - 10|0.1|x+36

0.01x^2 - 10|0.1|x - 2x+36=0

When we solve this equation,

We found,

 x = 12.5227 ≈ 12.53

Thus, the required solution is, x = 12.53

12) Here the height of rocket A in x second,

f(x) = -16x^2+74x+9

And, The height gain by the rocket B in x seconds,

g(x) = -16x^2+82x

If at x seconds both A and B gain the same height,

That is, f(x) = g(x)

⇒ -16x^2+74x+9= -16x^2+82x

⇒74x + 9 = 82x

⇒ 82x - 74x = 9

⇒ 8x = 9

⇒ x = 1.125 ≈ 1.13

Thus, the required solution is x = 1.13 seconds (approx)


4 0
3 years ago
Please give me the right answer
ivann1987 [24]

Answer:j

Step-by-step explanation:

If it’s closed it would be greater than -2 but since it’s open it’s equal or greater than

8 0
3 years ago
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