7. In the figure below, lines p and q are parallel. The measure of 23 = 126°.

Kira, goran, & joe sent a total of 90 text messages during the weekend. Goran sent 5 fewer messages than Kira. Joe sent 3 ti

MissTica

Answer:

Kira sent 19 text messages, Goran sent 14 text messages and Joe sent 57 text messages.

Step-by-step explanation:

Let be "k" the number of text messages that Kira sent during the weekend, "g" the number of text messages that Gora sent during the weekend and "j" the number of text messages that Joe sent during the weekend.

We know know that they sent a total of 90 text messages then:

$k+g+j=90$

Goran sent 5 fewer messages than Kira. This is:

$g=k-5$

And Joe sent 3 times as many messages as Kira. Then:

$j=3k$

The steps to solve this are:

- Substitute the second equation and the third equatio into the first equation and then solve for "k":

$k+(k-5)+(3k)=90\\\\5k-5=90\\\\5k=90+5\\\\k=\frac{95}{5}\\\\k=19$

- Substitute this value into the second equation to find "g":

$g=19-5=14$

- Substitute the value of "k" into the third equation to find "j":

$j=3(19)=57$

4 0

3 years ago

Can u please help with problem 1. (ONLY IF YOU KNOW)

Flura [38]

Is the question number 2 you need help

3 0

3 years ago

Read 2 more answers

The length of a swimming pool is 8m longer than its width and the area is 1o5m2?

Nina [5.8K]

Let the breadth be x
length=x+8
according to the question
area of the pool = l*b
105=x*x+8
if u solve this equation further u will get the answer

5 0

3 years ago

Read 2 more answers

Please help, I need input on if I did this correctly and you just substitute.

kow [346]

The value of h(t) when $t=\frac{15}{32}$ is 10.02.

Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

$$h\left(\frac{15}{32} \right)=10.02$

Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

8 0

3 years ago

The credit remaining on a phone card (in dollors) is a linear function of the total calling trime made with the card ( in minute

KATRIN_1 [288]

After 85 minutes of calls, there are $27.25 left on the card.

<h3>What is the remaining credit after 85 minutes of calls?</h3>

A linear equation in slope-intercept form is:

y = a*x + b

Where a is the slope.

If the line passes through two points (x₁, y₁) and (x₂, y₂) the slope is:

$a = \frac{y_2 - y_1}{x_2 - x_1}$

In this case, we know that the line passes through the points (22, 36.7) and (52, 32,20)

(points of the form (time, dollars)).

So the slope is:

$a = \frac{32.2 - 36.7}{52 -22} = -0.15$

The linear equation is then:

y = -0.15*x + b

To find the value of b, we use the point (22. 36.7)

36.7 = -0.15*22 + b

36.7 + 0.15*22 = b = 40

Then the linear equation is:

y = -0.15*x +40

The amount remaining in the credit card after 85 minutes is given by evaluating the above equation in x = 85.

y = -0.15*85 + 40 = 27.25

This means that after 85 minutes of calls, there are $27.25 left on the card.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

7 0

2 years ago