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kykrilka [37]
3 years ago
5

What is the equation of a line that is perpendicular to y = 3x -2 and passes

Mathematics
1 answer:
White raven [17]3 years ago
7 0

Answer:

A. y=-1/3x+10

Step-by-step explanation:

Perpendicular gradients(slopes) are negative reciprocals so

m=-1/3  then use the point (6,8) to find the equation of the line

y=mx+b

8=(-1/3)(6)+b

8=-2+b

b=10

y=-1/3x+10

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Determine whether the congruence is true or false.<br> 12 ≡ 10 mod 5
dolphi86 [110]

Answer:

The given congruence is false.

Step-by-step explanation:

Given : Expression 12 \equiv 10 \mod 5

To find : Determine whether the congruence is true or false ?

Solution :

The congruence is in the form x\mod y\equiv r

where, x is the dividend

y is divisor

r is the remainder

So, We find  10 \mod 5

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10 \mod 5=0

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4 years ago
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Answer:

Step-by-step explanation:

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3 years ago
For each of the following, state the equation of a perpendicular line that passes through (0, 0). Then using the slope of the ne
SVEN [57.7K]

Answer:

The answer is below

Step-by-step explanation:

a) y=3x-1

The standard equation of a line is given by:

y = mx + c

Where m is the slope of the line and c is the intercept on the y axis.

Given that y=3x-1, comparing with the standard equation of a line, the slope (m) = 3, Two lines with slope a and b are perpendicular if the product of their slope is -1 i.e. ab = -1. Let the line perpendicular to y=3x-1 be d, to get the slope of the perpendicular line, we use:

3 × d = -1

d = -1/3

To find the equation of the perpendicular line passing through (0,0), we use:

y-y_1=d(x-x_1)\\d\ is\ the \ slope:\\y-0=-\frac{1}{3} (x-0)\\y=-\frac{1}{3}x

To find  x if the point P(x, 4) lies on the new line, insert y = 4 and find x:

y=-\frac{1}{3}x\\ 4=-\frac{1}{3}x\\-x=12\\x=-12

b) y=1/4 x+2

Given that y=1/4 x+2, comparing with the standard equation of a line, the slope (m) = 1/4. Let the line perpendicular to y=1/4 x+2 be f, to get the slope of the perpendicular line, we use:

1/4 × f = -1

f = -4

To find the equation of the perpendicular line passing through (0,0), we use:

y-y_1=f(x-x_1)\\f\ is\ the \ slope:\\y-0=-4 (x-0)\\y=-4x

To find  x if the point P(x, 4) lies on the new line, insert y = 4 and find x:

y=-4}x\\ 4=-4x\\x=-1

8 0
3 years ago
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