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kykrilka [37]
2 years ago
5

What is the equation of a line that is perpendicular to y = 3x -2 and passes

Mathematics
1 answer:
White raven [17]2 years ago
7 0

Answer:

A. y=-1/3x+10

Step-by-step explanation:

Perpendicular gradients(slopes) are negative reciprocals so

m=-1/3  then use the point (6,8) to find the equation of the line

y=mx+b

8=(-1/3)(6)+b

8=-2+b

b=10

y=-1/3x+10

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Question 3 (1 point)
Nonamiya [84]

Answer:

I would think Jessica

Step-by-step explanation:

V36-->6  bc 6*6=36

Again, im pretty sure this is your answer not completely positive

5 0
3 years ago
URGENT!!
slava [35]

Answer:

a. 3/5 liters per hour

b .06 hours

Step-by-step explanation:

Change 40 minutes to a fraction of an hour

40 minutes/ 60 minutes = 2/3 hour

It takes 1 2/3 hours to fill the container

Changing to an improper fraction

(3*1+2)/3 = 5/3 hours

We want liters per hour

1 liter per 5/3 hours

1 ÷ 5/3

Copy dot flip

1 * 3/5 = 3/5 liters per hour

Change 100 ml to liters

We know 1000 ml  = 1 lt

100 ml * 1 lt/1000 ml = .1 lt

So 100 ml = .1 lts

.1 lt * 3/5 lt per hour

Changing the fraction to a decimal

.1 lt * .6 lt per hour

.06 hours

4 0
3 years ago
please help i will make brainlest if you have correct answers please put your answers in order like the pictures like 1 2 3 4 5
Kruka [31]

1. 22/25

2. -1 1/4

3. -1 7/10

4. 1 5/6

5. 1 2/3

8 0
3 years ago
Read 2 more answers
Simplify the following expression. (4x − 8)(4x + 8)
vitfil [10]

Answer:

16x^2 - 64

Step-by-step explanation:

(4x − 8)(4x + 8)

We recognize that this is the difference of squares

(a-b) (a+b) = a^2 - b^2

                 =(4x)^2 - 8^2

                 =16x^2 - 64

4 0
3 years ago
A surveyor standing on top of a cliff found that the angle of depression of a boat as sea is 22°. if the top of the cliff is 15m
Alex73 [517]

Answer:

From the photo above i interpreted the question and drew a triangle to make it easier to solve

Tan is used to solve the question as we were given opposite (as height of the cliff) and to find Adjacent ( the distance between the foot of the cliff to the boat)

Tan θ =Opp/Adj

Tan 22°=15/a

Cross Multiply

aTanθ=15°

Divide both sides by Tan 22

aTan22/Tan22 = 15/Tan 22

a = 15/Tan 22°

a = 37.13 m

Therefore the distance between the foot of the cliff to the boat is 37.13 metres

5 0
2 years ago
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