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3 years ago

Start at the origin. Move 10 units right and 4 units up.

Mathematics

2 answers:

UkoKoshka [18]3 years ago

8 0

Answer: (10, 4)

Step-by-step explanation:

Not sure of the question but that’s where the point ends up.

babymother [125]3 years ago

5 0

Answer:

(10,4)

if you go to the right. you would be in quadrant 1 so both numbers of the coordinates are even numbers. first number is x. and second is y.

x=10. y=4

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2 years ago

Read 2 more answers

Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

Verify each solution

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0

3 years ago

Read 2 more answers

What is the area of circle with a diameterms of 10 m

pentagon [3]

Answer:

exact area = 25(pi) m^2

approximate area = 78.54 m^2

Step-by-step explanation:

diameter = 10 m

radius = diameter/2 = 10 m / 2 = 5 m

area = (pi)r^2

area = (pi)(5 m)^2

area = 25(pi) m^2

area = 78.54 m^2

6 0

3 years ago

Hi please help me thanksss pls provide workings too thanks :)

anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

verified

Verified by Toppr

We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

2π

or x=

6n±2

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

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3 years ago

The quality-control manager of a large factory is concerned about the number of defective items produced by workers. Thirty work

kotegsom [21]

Answer:

a. There is no blocking variable, and incentive plans will be randomly assigned to the workers.

Step-by-step explanation:

The Randomized Complete Block Design (RCBD) is a standard experimental design where experimental units or subjects are grouped as blocks (also known as replicates). In RCBD, subjects within each block are randomly assigned to the experimental units within a block. RCBD is a type of design that reduces variability by controlling variation within each treatment, thereby enhancing the estimation of the treatment effects (combinations of the factor levels of the different factors).

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3 years ago

Start at the origin. Move 10 units right and 4 units up.​

Start at the origin. Move 10 units right and 4 units up.