Answer:
60 mph
Step-by-step explanation:
Given;
Total distance covered d = 440 miles
Average speed in the first 4 hours v1 = 50 mph
Total time taken for the whole trip t = 8:00 to 4:00pm
t = 16:00-8:00 = 8 hours
Firstly we need to calculate the distance covered during the first 4 hours;
d1 = average speed × time = v1 × t1
t1 = 4
d1 = 50 × 4 = 200 miles
Then we need to calculate the distance covered in the second period of the journey;
d = d1 + d2
d2 = d - d1
Substituting the values;
d2 = 440 - 200
d2 = 240 miles
The time taken for the second period of travel t2;
t2 = t -t1 = 8-4
t2 = 4 hours
Average speed = distance travelled ÷ time taken
The average speed for the second part of the trip v2 is;
v2 = d2 ÷ t2
Substituting t2 and d2;
v2 = 240 miles ÷ 4 hours
v2 = 60 mph
The average speed during the second part of the trip is 60 mph
Your answer is d
.............................
Answer:
6?
Step-by-step explanation:
??????????????????????????????????????????Is confoosed
Is easy?
Answer:
y = 0.325X + 7.5 ;
21.5 ;
R^2 = 0.7655 ;
r = 0.8749
Step-by-step explanation:
No. of loans originated ____ sheets of p/paper
45 ______________22
25 ______________ 13
50 _____________ 24
60 _____________ 25
40 _____________ 21
25 _____________ 16
35 _____________ 18
40 _____________ 25
Using the linear regression calculator : the linear model obtained is:
y = 0.325X + 7.5
y = predicted variable = sheets of photocopy paper
X = number of loans originated
0.325 = slope
Intercept = 7.5
B.)
X = 42
y = 0.325(42) + 7.5
y = 21.15
C.)
The Coefficient of determination as determined using the correlation coefficient calculator is :
R^2 = 0.7655 ; this means that about 76.55% of change in number of photocopy performed is explained by the number of loans originated.
D.) The correlation Coefficient (r) :
r = sqrt(R²)
r = sqrt(0.7655)
r = 0.8749
This shows that a strong positive correlation exists between the number of loans originated and the volume of photocopying done.
