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3 years ago

How did u get the area of the trapezoids tho.

Mathematics

1 answer:

GarryVolchara [31]3 years ago

3 0

Answer:

To find the area of a trapezoid, multiply the sum of the bases (the parallel sides) by the height (the perpendicular distance between the bases), and then divide by 2.

Step-by-step explanation:

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Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet,

MatroZZZ [7]

The two quadrilaterals are given similar .

In any similar figure sides are in proportion.The second largest side of quadrilateral ABCD is 16 ft .Let the second longest side of quadrilateral EFGH be x ft. These sides will be in proportion to each other .

The second shortest side of quadrilateral EFGH that is GF will be proportional to the third longest side of quadrilateral ABCD that is BC

We can form a proportion with the proportional sides:

$\frac{16}{x} =\frac{12}{18}$

To solve for x we cross multiply

12x=(16)(18)

12x=288

Dividing both sides by 12 we get

x=24.

The second longest side of quadrilateral EFGH is 24 ft.

6 0

3 years ago

50 Σ (4n - 1) = [? ] 1

Kay [80]

Answer:

5050

Step-by-step explanation:

3 0

3 years ago

Draw at least six different sized rectangles that have an area of 64 square units

olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

$A=x*y$

$A=64\ units^{2}$

$x*y=64$ --------> equation 1

let's assume different values of x to get the different values of y

case 1) For x=64 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/64$

$y=1\ units$

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

case 2) For x=32 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/32$

$y=2\ units$

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

case 3) For x=16 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/16$

$y=4\ units$

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

case 4) For x=30 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/30$

$y=\frac{32}{15} =2\frac{2}{15} \ units$

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

case 5) For x=40 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/40$

$y=1.60\ units$

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

case 6) For x=60 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/60$

$y=\frac{16}{15} =1\frac{1}{15} \ units$

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

3 0

2 years ago

Object A has a mass of 12 g and a volume of 8 cm3. Object B has a mass of 20 g and a volume of 8 cm3. Which object has a greater

Andreyy89

Answer:

Obj B, by 1 g/cm^3

Step-by-step explanation:

Obj A = 12g / 8cm^3 = 3g / 2cm^3 = 1.5 g/cm^3

Obj B = 20g / 8cm^3 = 5g / 2cm^3 = 2.5 g/cm^3

2.5 - 1.5 = 1 g/cm^3

4 0

3 years ago

Use pascal's triangle to expand the binomial (x+3)^4

ratelena [41]

Answer: the answer is in the photo pls check this out and hope this helps can u give me brainliest

Step-by-step explanation:

6 0

2 years ago