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Darina [25.2K]
3 years ago
5

2. A spy uses a telescope to track a rocket launched vertically from a launch pad 6 km away. The rocket travels upwards at a vel

ocity of 21.6 km per minute. Find the rate of change of the distance between the spy and the rocket when the rocket is 8 km in the air. Answer: 17.28 km/mim
NEED HELP ASAP
Mathematics
1 answer:
grandymaker [24]3 years ago
7 0

Answer:

The rate of change in distance between the spy and the rocket is 10.8 km/min,

or about 180 m/sec.

Step-by-step explanation:

At "Time=0" the rocket is 6km from the spy.

The rocket travels vertically 8km in about 0.37 minutes, calculated by 8km÷21.6km/min.

At that point, the rocket is 10 km from the spy., calculated by 6²+8²=10²

The difference is 4 kiilometers over 0.37minutes, about 22.2 seconds

Divide Distance by Time to get Rate:

4km/0.37min = 10.8 km/min

That is about 180 meters per second.

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timurjin [86]
What is 0.00340.78 correct to 3 significant figures?

a significant fugure is when the number lean solething ,so its can anyone except 0


so if we are reducing 0.00340.78 to 3 significant number

first we have to look for the significant nulber ,which are 3,4,7,8


so the answer can be 0.0034.7


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3 years ago
Which of these values could be the slope of the line? Select two options. –2 0 3
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Identify the terms and the like terms in the expression z+8-4z
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8 0
3 years ago
2. What is the value of x if the angles<br> within a triangle are 2x +1, 7x-2 and 3x<br> +5?
noname [10]

Answer:

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Step-by-step explanation:

The sum of all the three angles of any triangle is 180°

Putting sum of all the angles given equals to 180°

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                              2x+7x+3x+1-2+5=180°

                                                         12x+4=180°

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The value of the x is found on solving the given angles of the triangles.

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