Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Answer c: 2 and 3
Of course Q is on plane PQR. If S is as well, then QS is as well.
Answer:
4
Step-by-step explanation:
2x-4=3x-11 so add 4 to 11 and that’s -7 then subtract 2x from 3x so that’s 1x so 1x divides by -7 equals -7 so x=-7
