Sum of inside angles of a polygon= 180º(n-2)
n=number of sides.
This polygon has 6 sides, the sum of all its angles would be=180º(6-2)=720
let´s:
xº=inside angle
xº=720º-sum of the others inside angles.
xº=720º-(75º+130º+120º+105º+145º)=720º-575º=145º
yº=180º-xº=180º-145º=35º
Answer: yº=35º
Step-by-step explanation:
Hey there!
Now, let's look into figure.
angle ACB = 65° { Base angle of triangle ABC}
angle ACB + angle BAC + angle ABC = 180°
65° + 65° + angle ABC = 180°
angle ABC = 180°-130°
Therefore, angle 50°
angle EBD = 50° ( Vertically opposite angle)
Now;
angle EBD= angle DEB = 50° ( Base angle of triangle BDE )
angle BDE + angle DEB + angle EBD = 180° ( Sum of interior angle)
angle BDE = 180° -100°
Therefore, angle BDE = 80°.
Now, 80° + 14x + 2 = 180° { being linear pair}
14x = 180°-82°
14x = 98°

X = 7°
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Answer:
The answer is 6 1/10
Step-by-step explanation:
4 1/2 + 1 3/5
5
1/2 + 3/5
5/10 + 6/10 = 11/10
6 1/10
2% of 300 would be 6 and 6 rounded to the nearest 100th is 6.00
Answer: c.41.31
Step-by-step explanation: