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3 years ago

Please solve this equation fast

Mathematics

1 answer:

omeli [17]3 years ago

6 0

Answer:under is answer

Step-by-step explanation:

5/8+3/4=11/8 then,-2/3-5/6=-3/2

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12 + 4x > 24 or 10 - 12x > 22

Wewaii [24]

Answer:

10 - 12 × > 22 Yan Yong sagot

8 0

3 years ago

HELP PLEASEE!!!!

ss7ja [257]

Answer:

See below ~

Step-by-step explanation:

$\textsf {Each of the steps has been reasoned below :}$

$\implies \textsf {3x - 2 = 4 (Given)}$

$\implies \textsf {3x = 6 (Addition Property of Equality)}$

$\implies \textsf {x = 2 (Division Property of Equality)}$

$\textsf {In the second step, the property has been applied}\\\textsf {by adding 2 to each side of the equation.}$

$\textsf {In the third step, the property has been applied by dividing 3 on each side.}$

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2 years ago

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What is the indicated missing angle can someone pls help me

Karolina [17]

Answer:

Step-by-step explanation:

Since this is a right triangle, we can use a trig function

cos theta = adjacent/ hypotenuse

cos ? = 52/ 60

Take the inverse cos of each side

cos ^ -1 cos ? = cos ^ -1 ( 52/60)

? =29.92643487

To the nearest degree

? = 30

6 0

4 years ago

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When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$

Hence, a 99% confidence interval for the true proportion of all college students who own a car : 0.332 < p < 0.490

3 0

3 years ago

If $3,000 is deposited at the end of every six months into an account that earns 10% semiannually, find the amount after 10 year

lesya [120]

Answer:

7959.83

Step-by-step explanation:

A = P ( 1+r/n)^ nt

Where A is the amount in the account

P is the principal

r is the rate

n is the number of compoundings per year

t is the years

A =3000 ( 1+.10/2)^ 2*10

A =3000 ( 1+.05)^ 20

=7959.83

6 0

3 years ago

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