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Ludmilka [50]
3 years ago
9

Jaime collects donations to make packages for the children in a local hospital he has 45 books and 30 stuffed animals and wants

to make identical packages what is the greatest number of packages that Jaime can make using all the books and stuffed animals?
Mathematics
2 answers:
stepan [7]3 years ago
6 0

Answer:

15 packages

Step-by-step explanation:

We are asked to find the greatest number of packages that Jaime can make using all the books and stuffed animals. This means we solve this question using GCF method

We have to find the factors of 30 and 45

The factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30

The factors of 45 are: 1, 3, 5, 9, 15, 45

Then the greatest common factor is 15.

Hence, the greatest number of packages that Jaime can make using all the books and stuffed animals is 15 packages

Anika [276]3 years ago
4 0

Answer:

15

Step-by-step explanation:

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Step-by-step explanation:

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Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

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Answer:

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