2 years ago

Find the perimeter of the polygon with the vertices A (-1,5), B (-1,-4), C (-6,-4), and D (-6,5)

Mathematics

1 answer:

ch4aika [34]2 years ago

5 0

Schools almost over, good luck!!

You might be interested in

Choose Yes or No to tell if the fraction 3/5 will make each equation true.

Vinvika [58]

Yes
no
no
yes
i hope it helped.

4 0

2 years ago

Read 2 more answers

Determine the slope and y-intercept of each graph. Then, write the equation of the graph in slope-intercept form. please help

olchik [2.2K]

Answer:

slope = 2

y intercept = ( 0 , -1 )

equation:

y = 2x - 1

Step-by-step explanation:

7 0

2 years ago

Volume of a right rectangular prisms the side lengths are 1ft,2ft,3ft,4ft,and 5ft.

In-s [12.5K]

The volume would be 120sqft.

6 0

2 years ago

Read 2 more answers

There 10 people inside the house then the house caught on fire but only 2/3 escaped how much is still in the building?

slega [8]

Answer:

6.67 is the awnser or 6.6666666666

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

2 years ago