Answer:
6 number treat sacks and
each sack having 5 pencils and 7 smiley face stickers.
Step-by-step explanation:
Given that:
Number of pencils = 30
Number of smiley face stickers = 42
Mrs. MaryAnn wants to divide everything in identical treat sacks so that there are no leftovers.
To find:
The number of greatest number of treat sacks.
Solution:
First of all, we need to find the Highest Common Factor of the two numbers.
Factorization method:
![30 = \underline2\times \underline3\times 5](https://tex.z-dn.net/?f=30%20%3D%20%5Cunderline2%5Ctimes%20%5Cunderline3%5Ctimes%205)
![42 = \underline2\times \underline3 \times 7](https://tex.z-dn.net/?f=42%20%3D%20%5Cunderline2%5Ctimes%20%5Cunderline3%20%5Ctimes%207)
Here, the common numbers 2 and 3.
So, highest common factor is ![2\times 3 = 6](https://tex.z-dn.net/?f=2%5Ctimes%203%20%3D%206)
If we divide 30 by 6, we get 5 and
If we divide 42 by 6, we get 7
So, if we take 5 pencils and 7 smiley face stickers in one treat sack and if we make 6 such treat sacks then there will be equal division and no leftovers.
Therefore, the answer is:
6 number treat sacks and
each sack having 5 pencils and 7 smiley face stickers.