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Alisiya [41]
3 years ago
14

Which group shows 0.25 of the faces smiling?

Mathematics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

My dude the groul that shows that tiny bit of smiling must be the beatles or backstreet boys

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If 50 grams of a radioactive substance decomposed to 42 grams in 2 years, then, to the nearest gram, the amount left after 5 yea
Inga [223]

Answer:

30 grams

Step-by-step explanation:

50-42=8

8÷2=4

4=1 year

5×4=20

50-20=30

Hope u can understant

3 0
2 years ago
Four friends attend a school play and pay $6.75 per ticket. Each also buys a Healthy Snack Bag sold by the Theater Club. If the
gogolik [260]

Answer:

$2.5

Step-by-step explanation:

Multiply 4 friends by $6.75 and find the product.

Subtract $27 from $37

Divide 10 by 4

6 0
2 years ago
Read 2 more answers
One year Ron had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched)
Arada [10]

Answer:

Ron's ERA has a z-score of -2.03.

Karla's ERA has a z-score of -1.86.

Due to the lower z-score, Ron had a better yean than Karla relative to their peers.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Since the lower the ERA, the better the pitcher, whoever's ERA has the lower z-score had the better year relative to their peers.

Ron

ERA of 3.06, so X = 3.06

For the males, the mean ERA was 5.086 and the standard deviation was 0.998. This means that \mu = 5.086, \sigma = 0.998

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.06 - 5.086}{0.998}

Z = -2.03

Ron's ERA has a z-score of -2.03.

Karla

ERA of 3.28, so X = 3.28

For  the females, the mean ERA was 4.316 and the standard deviation was 0.558. This means that \mu = 4.316, \sigma = 0.558

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.28 - 4.316}{0.558}

Z = -1.86

Karla's ERA has a z-score of -1.86.

Which player had the better year relative to their peers, Ron or Karla?

Due to the lower z-score, Ron had a better yean than Karla relative to their peers.

5 0
3 years ago
(4.3*10^4)^2 in scientific notation
xeze [42]
1.849x10^9 or 1.849e9
3 0
2 years ago
in 1991, a gallup poll reported this percent to be 79%. using the data from this poll, test the claim that the percent of driver
snow_lady [41]

We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.

Given,

The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.

In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.

To report the large-sample z statistic and its p-value,

Null hypothesis,

H₀ : p = 0.79

Alternative hypothesis,

Ha : p < 0.79

Level of significance, α = 0.01

Under H₀

Test statistic,

Z_0= \frac{\hat p - p}{\sqrt{\frac{p(1-p)}{n} }  }

Z₀ = -7.948

The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by

P-value = P(z <-7.945)

            = 0.000     (from z-table)

Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.

To learn more about hypothesis click here:

brainly.com/question/17173491

#SPJ4

5 0
1 year ago
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