$\bf 4(x+5)^3(x-1)^2-(x+5)^4\cdot 2(x-1)
\\\\\\
4(x+5)^3(x-1)^2-2(x-1)(x+5)^4
\\\\\\ \underline{2}\cdot 2\underline{(x+5)^3}(x-1)\underline{(x-1)}~-~\underline{2}\underline{(x-1)}(x+5)\underline{(x+5)^3}\leftarrow 
\begin{array}{llll}
notice~the\\
common\\ \underline{factors}
\end{array}
\\\\\\
2(x+5)^3(x-1)~[~2(x-1)-(x+5)~]
\\\\\\
2(x+5)^3(x-1)~[2x-2-x-5]\implies 2(x+5)^3(x-1)(x-7)$

5 0

3 years ago

4 1/2 cups converted to fluid ounces

Dmitry_Shevchenko [17]

Answer:

4.5 cup to oz is 36 FLUID OUNCES

6 0

3 years ago

How do i solve for this?

Firdavs [7]

9514 1404 393

Answer:

97.42 square units

Step-by-step explanation:

The area of a sector is given by ...

A = (1/2)r²θ

where r is the radius (12.2) and θ is the central angle in radians. Here, you're given the central angle as 75°, so you need to convert that to radians.

75° = (75°)×(π/180°) radians = (5/12)π radians

Then the area is ...

A = (1/2)(12.2²)(5π/12) = 744.2π/24 ≈ 97.42 . . . square units

Equivalently, you can find the area of the circle in the usual way:

A = πr² = π(12.2²) ≈ 467.59465

Then, multiply by the fraction of the circle that is shaded (75°/360°)

sector area = (467.59465)(75/360) = 94.42 . . . square units

5 0

3 years ago