Answer:
There are 2,184 ways to select a first-place, second-place, and third-place winner.
The probability that all three winners are from Midland High is 0.0275.
The probability that all three winners are from Cassville High is 0.0549
Step-by-step explanation:
Since a local chess tournament gives medals for first, second, and third place, and there are five students from Midland High, three students from Leasburg High, and six students from Cassville High competing in the tournament, to determine which of the following statements are true, the following calculations must be performed:
A) There are 2,184 ways to select a first-place, second-place, and third-place winner.
5 + 3 + 6 = 14
14 x 13 x 12 = X
182 x 12 = X
2.184 = X
B) The probability that all three winners are from Midland High is 0.0275.
5/14 x 4/13 x 3/12 = X
0.02747 = X
C) The probability that all three winners are from Leasburg High is 0.0046.
3/14 x 2/13 x 1/12 = X
0.00274 = X
D) The probability that all three winners are from Cassville High is 0.0549
6/14 x 5/13 x 4/12 = X
0.0549 = X
