Question

On a cool summer morning in East Lansing, Michigan, the temperature was 7 ℃elsius and the air was saturated with​ RH​ = 100%. That afternoon, the temperature rose to 29° Celsius. If the same air mass remained in place all day (meaning the moisture content did not change throughout the day).
Required:
a. Would the relative humidity increase or decrease in the afternoon?
b. What was the relative humidity during that afternoon (rounded to the nearest percent)?

Answer 1

Answer:

The correct answer is -

a) The relative humidity decreases with an increase in temperature.

b) 25%

Explanation:

The dew point (Td) is the temperature at which the Relative humidity (RH) is 100%. So in the given question dew point, is (Td) is 7° C. The RH can be calculated by the formula:

$RH: =100*\frac{(EXP((17.625*TD)/(243.04+TD))}{EXP((17.625*T)/(243.04+T)))}$

Putting the values of Td and T we get RH=

$RH: =100*\frac{(EXP((17.625*7)/(243.04+7))}{EXP((17.625*29)/(243.04+29)))}$

= 25.02 or 25 %.