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hram777 [196]
2 years ago
10

Ms. Thornton is buying treats for her top 10 algebra students in each of her two classes (20 treats total). She’s only willing t

o spend $30 and finds individualized candy packs for $1.75 each. What is the maximum number of packs that she will be able to buy? Will that be enough for all of her students?
Mathematics
1 answer:
Paladinen [302]2 years ago
5 0

Answer:

Mrs Thornton can buy almost 17 candy packs if she has $30 to spend and one pack cost $1.75.

No, it will not be enough because total students are 20 and total candy packs that can be bought are 17.

Step-by-step explanation:

Total treats to buy = 20

Total cost to spend = $30

Price of one candy pack = 1.75

We need to find:

a) What is the maximum number of packs that she will be able to buy?

Price of 1 candy pack = $1.75

If she spends $30, divide 30 by 1.75 to get the number of candy packs she can buy

Number of candy packs = \frac{30}{1.75} = 17.14 \approx 17

So, Mrs Thornton can buy almost 17 candy packs if she has $30 to spend and one pack cost $1.75

b)  Will that be enough for all of her students?

No, it will not be enough because total students are 20 and total candy packs that can be bought are 17.

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Answer:

x = 58 degrees

Step-by-step explanation:

Angle K (which is x) and Angle I are congruent corresponding angles with one another, so if, as an example, Angle I was 10, Angle K would also be 10.

<u><em>All you need to do in this case is add Angle H (56) and Angle A (66) together:</em></u>

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Answer:

(a) 71.00%

(b) 63.00%

Step-by-step explanation:

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3 years ago
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devlian [24]

Answer:

a = 1

Step-by-step explanation:

1. distribute the -6 on the left into the parentheses. you should get -36a + 30.

2. on the side right of the =, distribute the -2 to get -16 + 10a.

now it should look like -36a + 30 = -16 + 10a.

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3 years ago
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