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2 years ago

Which of the following is the ratio of boys to girls in tamir's math class?

Mathematics

2 answers:

notka56 [123]2 years ago

6 0

Answer:

12/15

Step-by-step explanation:

you put the number of boys over the number of girls

sometimes you can simplfy but it looks like the answer choice doens't want you too

WARRIOR [948]2 years ago

4 0

The answer for your question is 12/15

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2 years ago

In how many ways can you arrange MATHEMATICS if duplication of the arrangement are not allowed?

sukhopar [10]

Answer:

4989600 ways

Step-by-step explanation:

From the question,

The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)

⇒ n!/(r₁!r₂!r₃!) ways

Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.

Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2

Substitute these value into the expression above

11!/(2!2!2!) = (39916800/8) ways

4989600 ways

Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways

7 0

2 years ago

What is the balance after 15 years in a savings account that earns 2% interest compounded bimonthly when the initial deposit is

Ierofanga [76]

Answer:

$1348.07

Step-by-step explanation:

Hello!

<h3>Compound Interest Formula: $A = P(1 + \frac rn)^{nt}$ </h3>

A = Account Balance
P = Principle/Initial Amount
r = Rate of Interest (decimal)
n = Number of times compounded (per year)
t = Number of Years

<h3>Given Information</h3>

Account Balance = ?
Principle Amount = $1000
Rate of Interest = 0.02

Why is the Rate 0.02?

This is because we are gaining money, so the multiplier should be greater than 1. We already added 1, which is 100% so you simply add the 0.02 for the extra 2%.

Number of times compounded per year = 6

This is because it is being compounded bi-monthly, or once every 2 months. 12 months divided by 2 months is 6 months, so 6 times a year.

Number of years = 15

<h2>Solve </h2>

Solve by plugging in the given values into the formula.

$A = P(1 + \frac rn)^{nt}$
$A = 1000(1 + \frac {0.02}{6})^{6*15}$
$A = 1000(1 + 0.00333...)^{90}$
$A = 1000(1.00333...)^{90}$
$A = 1000(1.145743)$
$A \approx 1457.43$

This is really close to the first option, and since there is rounding involved with the repeating decimal, the first option should be correct.

The answer is $1348.07.

3 0

1 year ago