Answer:
The graph has been moved 7 units to the left and 8 units down.
Step-by-step explanation:
When numbers are added directly to the "x" value, the graph shifts to the left. If negative numbers are added directly to the "x" value, the grap shifts to the right. Therefore, if there is a +7 directly altering the "x" value, the function shifts 7 units to the left.
When a number is added to the overall function, it shifts upwards. If this number is negative, the entire function shifts downwards. Therefore, if there is a -8 outside altering the function, then it has been shifted 8 units down.
Answer:
y= 1x + -5
Step-by-step explanation:
y= mx + b
To obtain the probability of obtaining heads at least 3 times out of 5 times we recall that in her simulation <span>she
assigned odd digits to represent heads and even digits to represent
tails. Thus, we count the simulated numbers to see in how many numbers
do we have 3 or more odd digits.
Below, the simulated numbers with 3 or more odd digits are bolded.
</span> <span>32766 53855 34591 27732
47406 31022 25144 72662
03087 35521 26658 81704
56212 72345 44019 <span>65311
</span>
We have 6 simulated numbers having 3 or more odd digits.
Therefore, </span><span>P("heads" at least 3 out of 5 times) = 6 / 16 = 3 / 8.</span>
Answer:
4/5 and the second one is 3
Step-by-step explanation:
the fact that you dont, know this is sad.
Hey there Kia!
![\left[\begin{array}{ccc}40/2=20 \ ; \ 19/2=9.5\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D40%2F2%3D20%20%5C%20%3B%20%5C%2019%2F2%3D9.5%5Cend%7Barray%7D%5Cright%5D%20)
Your answer should look like the following.
![\left[\begin{array}{ccc} \frac{19}{20y}= \frac{9.5}{40y^3} \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cfrac%7B19%7D%7B20y%7D%3D%20%5Cfrac%7B9.5%7D%7B40y%5E3%7D%20%20%5Cend%7Barray%7D%5Cright%5D%20)
Hope this helps you!
