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denpristay [2]
3 years ago
10

In the class interval 5-10, find the

Mathematics
2 answers:
stealth61 [152]3 years ago
5 0
(i) lower limit = 5
(ii) upper limit = 10
(iii) class mark = 15
(iv) class size = 5
slava [35]3 years ago
3 0

Answer:

lower limit = 5

upper limit = 10

class mark = lower limit + upper limit ÷ 2 = 7.5

class size = upper limit - lower limit

= 10-5 = 5

Step-by-step explanation:

I hope this help you have an great day and safe health

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Answer:

87.5 %

Step-by-step explanation:

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x = (64-8)×100/64

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3 years ago
Find the point P on the line yequals=33x that is closest to the point (60 comma 0 )(60,0). What is the least distance between P
scoray [572]

Answer:

18\sqrt{10}$ units

Step-by-step explanation:

We are given the equation of the line y=3x and a point, say Q(60,0) outside of that line.

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Let P(x,y) be the desired point. Since it is on the line y=3x, it must satisfy the line.

If x=a, y=3a, so the point P has the coordinates (a,3a).

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To minimize D, we find its derivative

\dfrac{dD}{da}=\dfrac{10a-60}{\sqrt{10a^2-120a+3600} }\\$Setting \dfrac{dD}{da}=0\\10a-60=0\\10a=60\\a=6

Therefore, the y-coordinate for P is 3*6=18.

The point P=(6,18).

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D =\sqrt{10(6)^2-120(6)+3600}\\=\sqrt{3240}\\=18\sqrt{10}$ units

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Step-by-step explanation:

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d) the real numbers with decimal representationsconsisting of all 1’s or 9’s

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