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2 years ago

Identify 3 major arcs of circle that contain point A?

Mathematics

1 answer:

natita [175]2 years ago

3 0

Answer:

Minor Arcs (two capital letters) Arcs that have a degree measure of less than 180 degrees.

Major Arc (three capital letters) Arcs that have a degree measure greater than 180 degrees.

Semi Circle (three capital letters) Arcs that have a degree measure equal to 180 degrees.Step-by-step explanation:

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Formula for the surface area of a cylinder, SA = 2ar2 + 2arh. Solve for h.

MakcuM [25]

Answer:

$h=\frac{SA-2\pi r^2}{2\pi r}$

Step-by-step explanation:

The formula for the surface area of a cylinder is:

$SA=2\pi r^2+2\pi rh$

And we want to solve for the height h.

First, subtract $2\pi r^2$ from both sides. This yields:

$2\pi rh=SA-2\pi r^2$

Now, divide both sides by $2\pi r$ . This yields:

$h=\frac{SA-2\pi r^2}{2\pi r}$

And we're done!

8 0

3 years ago

Translate the following statement into an appropriate algebraic statement: The number of text messages sent times $0.15 plus the

Oxana [17]

Actually the answers A since t is for text messages and it costs .15 and m is minutes and costs .07 so we add those two together to he .15t+ .07m then there's a discount of 2.50 so we subtract. So our final equation is .15t + .07m - 2.50 = C

7 0

3 years ago

Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ

liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

$\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy$

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

Mx(x,y) = d/dx 8x²y = 16xy
Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy$

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2$

We conclude that the line integral is 1/2

4 0

3 years ago

Select the most appropriate response

Sergio039 [100]

Answer:its A

Step-by-step explanation:

5 0

3 years ago

Can someone help me out with this?

myrzilka [38]

Where the ball ended

4 0

3 years ago