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makvit [3.9K]
3 years ago
8

Linear, exponential or neither?

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

Linear

Step-by-step explanation:

The previous term plus 4.

1, 5, 9, 13 plotting these points would make a straight line!

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Sara is serving wings and burgers at her party. Wings cost $6.00 per serving and burgers are $3.00 each. Sara knows that at leas
11111nata11111 [884]
The answer is 3.

$6 x 6 = 36
45 - 36 = 9
9 divided by 3 = 3 burgers
6 0
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PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Triss [41]

Answer:

December

Step-by-step explanation:

December:  acoustic/ electric =10/12 = 5/6

January : 13/16

Get a common denominator of 48

5/6 *8/8 = 40/48 for December

13/16 * 3/3 =39/48 for January

December has a higher ratio

6 0
3 years ago
Which of the following is equivalent to the given equation 7x2 = 98x - 343
professor190 [17]

Answer:

(x-7)

Step-by-step explanation:

i guessed and got it right

6 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
How do you find the equation of a line with Guassian elimination given two points?
Paraphin [41]

Answer:

  The solution is similar to the 2-point form of the equation for a line:

  y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)

Step-by-step explanation:

Using the two points, write two equations in the unknowns of the equation of the line.

For example, you can use the equation ...

  y = mx + b

Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:

  b + (x1)m = (y1)

  b + (x2)m = (y2)

The corresponding augmented matrix for this system is ...

  \left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]

____

The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.

  0 + (x2 -x1)m = (y2 -y1)

Dividing by the value in row 2 column 2 gives you the value of m:

  m = (y2 -y1)/(x2 -x1)

This value can be substituted into either equation to find the value of b.

  b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation

7 0
3 years ago
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