The answer is 3.
$6 x 6 = 36
45 - 36 = 9
9 divided by 3 = 3 burgers
Answer:
December
Step-by-step explanation:
December: acoustic/ electric =10/12 = 5/6
January : 13/16
Get a common denominator of 48
5/6 *8/8 = 40/48 for December
13/16 * 3/3 =39/48 for January
December has a higher ratio
Answer:
(x-7)
Step-by-step explanation:
i guessed and got it right
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height
Answer:
The solution is similar to the 2-point form of the equation for a line:
y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)
Step-by-step explanation:
Using the two points, write two equations in the unknowns of the equation of the line.
For example, you can use the equation ...
y = mx + b
Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:
b + (x1)m = (y1)
b + (x2)m = (y2)
The corresponding augmented matrix for this system is ...
![\left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26x1%26y1%5C%5C1%26x2%26y2%5Cend%7Barray%7D%5Cright%5D)
____
The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.
0 + (x2 -x1)m = (y2 -y1)
Dividing by the value in row 2 column 2 gives you the value of m:
m = (y2 -y1)/(x2 -x1)
This value can be substituted into either equation to find the value of b.
b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation