The first step to solve the equation 1 1/2 + 2 1/3 = ? is (a) First, you should convert the mixed numbers to improper fractions.
<h3>How to determine the first step?</h3>
The equation is given as:
1 1/2 + 2 1/3 = ?
The terms in the equation are mixed numbers.
So, the first stem is to convert the mixed numbers to improper fractions
Hence, the true statement is (a) First, you should convert the mixed numbers to improper fractions.
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Answer:
x = -5
, y = 0
Step-by-step explanation:
Solve the following system:
{4 x + 7 y = -20 | (equation 1)
2 x - 5 y = -10 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x + 7 y = -20 | (equation 1)
0 x - (17 y)/2 = 0 | (equation 2)
Multiply equation 2 by 2/17:
{4 x + 7 y = -20 | (equation 1)
0 x - y = 0 | (equation 2)
Multiply equation 2 by -1:
{4 x + 7 y = -20 | (equation 1)
0 x+y = 0 | (equation 2)
Subtract 7 × (equation 2) from equation 1:
{4 x+0 y = -20 | (equation 1)
0 x+y = 0 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -5 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = -5
, y = 0
Great question! that means bad weather = $$$$. good weather= no $$$
The value of the exponents in simple exponential form is
.
The mathematical operation of exponentiation, written as bⁿ, involves the base number (b) and the exponent (or power) number (n). The way to say this word is "b (elevated) to the (power of) n."
- Exponentiation corresponds to repeated base multiplication when n is a positive integer since bⁿ is the outcome of multiplying n bases. The exponent is often displayed to the right of the base as a subscript.
- The phrase "b to the nth power" or simply "b to the nth" is used to refer to bn. Other variations are "b (raised) to the power of n," "the nth power of b," and "b to the power of n" and "b to the nth power,"
The properties of exponents tell us that when the bases are equal then on multiplication the powers are added and on division the powers are subtracted.
![\sqrt[5]{5^y} \cdot(5^4)^3 = 5^{\frac{y+60}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B5%5Ey%7D%20%5Ccdot%285%5E4%29%5E3%20%3D%205%5E%7B%5Cfrac%7By%2B60%7D%7B5%7D%20%7D)
![\sqrt[5]{5^x} \cdot(5^4)^3 = 5^{\frac{x+60}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B5%5Ex%7D%20%5Ccdot%285%5E4%29%5E3%20%3D%205%5E%7B%5Cfrac%7Bx%2B60%7D%7B5%7D%20%7D)
Therefore the properties of exponents can be used to find the exponential solutions.
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$732 I believe, hope this helps! <3