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3 years ago

13

Customers generally find waiting in line to be an unpleasant experience. In addition to reducing the length of the wait itself,

what other steps could a business take to reduce the frustration customers experience while waiting?

1 answer:

garri49 [273]3 years ago

5 0

Answer:

OOP

Step-by-step explanation:

You might be interested in

Danny earns a monthly allowance of twenty dollars and extra seventy five cents every time he is nice to his mom. Avery earns a m

Lerok [7]

Answer:

Danny: y-=.75x+20

Avery: y=1.25x+18

Step-by-step explanation:

To write a system of equations, it usually equals y=mx+b. Since Danny and Avery both earn the set monthly allowance of 20 and 18 dollars respectively, those numbers go on the variable b since it's a set amount and they start off with that amount of money if they weren't nice to their mom at all.

Since we are trying to find the overall amount of money, let y=total money a child earns every month and x=how many times the child is nice to their mother.

The extra .75 cents Danny earns go under the variable m because it is dependent on how many times he is nice to his mom. Along with Avery.

4 0

2 years ago

What is the rate of change between (1,15) (3,45)?

Ksivusya [100]

Answer:

15

Step-by-step explanation:

Rate of change or slope or gradient of a line passes two points (x1, y1) and (x2, y2) could be calculated by:

(y2 - y1)/(x2 - x1)

=> Rate of change of the line passing (1,15) and (3,45):

(45 - 15)/(3 - 1) = 30/2 = 15

3 0

2 years ago

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0

1 year ago

A manufacturing company plans to progressively increase its production capacity over the next few quarters. (A quarter is a peri

mihalych1998 [28]

Answer:

5 months

Step-by-step explanation:

We assume that y represents production capacity, rather than <em>increase</em> in production capacity. Then we want to solve the 6th-degree equation ...

x^6 -25x^4 +199x^2 -4975 = 0

This can be factored in groups as ...

x^4(x^2 -25) + 199(x^2 -25) = 0

(x^4 +199)(x^2 -25) = 0

This has 4 complex solutions and 2 real solutions.

x^2 = 25

x = ±5

The duration required for capacity to reach 4975 units is 5 months.

7 0

3 years ago

UNO [17]

T - Shirts = $10
SweatShirts = 15$

24 *15 =360$

105 - 24 = 81

81 * 10 = 810$

810 + 360 = 1170$

T shirts = 81
Sweat= 24. /A\is the correct Answer

8 0

3 years ago