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3 years ago

13

Customers generally find waiting in line to be an unpleasant experience. In addition to reducing the length of the wait itself,

what other steps could a business take to reduce the frustration customers experience while waiting?

1 answer:

garri49 [273]3 years ago

5 0

Answer:

OOP

Step-by-step explanation:

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Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of <em>t</em> for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0

3 years ago

What is the value of 9x^2 + 13x – 15, if x = 2

Paladinen [302]

Step-by-step explanation:

Given,

$9 {x}^{2} + 13x - 15$

and

$x = 2$

Substitute x = 2 into expression.

$9 {x}^{2} + 13x - 15 = 9( {2}^{2} ) + 13(2) - 15 \\ = 9(4) + 26 - 15 \\ = 36 + 26 - 15 \\ = 62 - 15 \\ = 47$

3 0

3 years ago

Read 2 more answers

The coordinates of the vertices of □PQR are (-2,5), Q(-1,), and R(7,3). Determine whether □ PQR is a right triangle. Show Your W

alexdok [17]

Answer:

Slope of PQ

m

r

=

y

Q

−

y

P

x

Q

−

x

P

=

1

−

5

−

1

−

(

−

2

)

=

−

4

Slope of QR

m

p

=

y

R

−

y

Q

x

R

−

x

Q

=

3

−

1

7

−

(

−

1

)

=

1

4

Slope of RP

m

q

=

y

R

−

y

P

x

R

−

x

P

=

3

−

5

7

−

5

=

−

1

Since slopes PQ & PR,

m

r

=

−

1

m

p

, it's a right triangle

4 0

3 years ago

Bradley answered 80% of the questions on his science test correctly. There were 30 questions on the test, and all the questions

son4ous [18]

Answer:

24 correct questions

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the slope of the line that passes through (-53, -2) and (-54, 91).

cricket20 [7]

Answer:

x1=-53 y1=-2

x2=-54. y2=91

slopes= y2-y1

---------

x2-x1

91-(-2)

-----------------

= -54-(-53)

91+2

= ----------

-54+53

= 93

-------

-1

8 0

3 years ago