Answer: Yes I need followers go follow Im_Baby_Yoda_
32,000
Step-by-step explanation:2+6=8*4000=32000
The least number of cases and envelopes so that there would be no remainder can be determined by finding their least common multiple. The solution is as follows
4 | 20 12
---------------
| 5 3
-------------------
Multiplying 4*5*3 = 60. The least common multiple is 60. Thus, there should be at least 60 each of the envelopes and the packets.
Number of mailing envelopes = 20x = 60
x = 3
Number of packets = 12y = 60
y = 5
That would be 3 packs of the envelopes, and 5 packs of the packets.
Answer:
1.88×10^15
Step-by-step explanation:
3.2*10^2 LY ( 5.88*10^12 mi/LY)
= 18.8 * 10^14 mi
= 1.88 * 10^15 mi
The operation would be: 1-1/12-1/6=1-3/12=9/12=3/4
Good luck!
Answer: 7
Step-by-step explanation:
4.25+6.75=11
11+7=18
18-11=7