Answer:
Area_shaded = 2543.742 ft^2
Step-by-step explanation:
First we find the area of the external triangle
A_triangle = base*height*0.5
A_triangle = (92 ft)*(84 ft)*0.5 = 3864 ft^2
Then we find the area of the pool (circle)
A_circle = pi*radius^2
A_circle = 3.1416*(20.5 ft)^2 = 1320.257 ft^2
The area of the shaded region
Area_shaded = A_triangle - A_circle
Area_shaded = 3864 ft^2 - 1320.257 ft^2 = 2543.742 ft^2
Answer:
69.282 m
Step-by-step explanation:
We can use the trigonometry of right triangles to solve this, since we are in the presence of a right triangle with acute angle 30 degrees, opposite side unknown (the vertical height of the cliff), and adjacent side equal to 120 m.
we use the tangent function to solve for the unknown, as shown below:
tan(30) = x/120
x = 120 * tan(30) = 69.282 m
<span>5a + 2 = 6 - 7a
5a + 7a = 6 - 2
12a = 4
a = 4/12 = 1/3
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