ANSWER
(3,-1)
EXPLANATION
The given system of equations is :
5x+y=14
2x-y=7
For the first equation when x=0,
5(0)+y=14
y=14
The y-intercept is (0,14).
When y=0, 5x+0=14
The x-intercept is (2.8,0).
We plot the intercepts and draw a straight line through them to obtain the graph of 5x+y=14 as shown in the attachment.
We repeat the same process for the second equation 2x-y=7.
The intercepts are (0,-7) and (3.5,0)
The solution to the system is the point of intersection of the two straight lines.
The two straight lines intersected at
(3,-1)
Hence x=2, y=-1
(3,-1)
EXPLANATION
The given system of equations is :
5x+y=14
2x-y=7
For the first equation when x=0,
5(0)+y=14
y=14
The y-intercept is (0,14).
When y=0, 5x+0=14
The x-intercept is (2.8,0).
We plot the intercepts and draw a straight line through them to obtain the graph of 5x+y=14 as shown in the attachment.
We repeat the same process for the second equation 2x-y=7.
The intercepts are (0,-7) and (3.5,0)
The solution to the system is the point of intersection of the two straight lines.
The two straight lines intersected at
(3,-1)
Hence x=2, y=-1