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ella [17]
3 years ago
5

Find the probability of each event. A gambler places a bet on a horse race. To win, he must pick the top three finishers in any

order. Eight horses of equal ability are entered in the race. Assuming the horses finish in a random order, what is the probability that the gambler will win his bet?
Mathematics
1 answer:
Lina20 [59]3 years ago
3 0

Answer: \dfrac{1}{56}

Step-by-step explanation:

Total horses = 6

Number of ways to choose top 3 finishers in order = 3! = 6

Number ways to select 3 horses out of 8 in order = ^8P_3  [By permutations]

=\dfrac{8!}{(8-3)!}=\dfrac{8!}{5!}=8\times7\times6=336

Now, the probability that the gambler will win his bet =

\dfrac{\text{Number of ways to choose top 3 finishers }}{\text{Number ways to select 3 horses out of 8 in order}}

=\dfrac{6}{336}\\\\=\dfrac{1}{56}

Hence, the required probability =  \dfrac{1}{56}

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storchak [24]

Answer:

12a + 6

Step-by-step explanation:

given 3(4a + 2)

multiply each term in the parenthesis by the 3 outside ( distributive law )

= (3 × 4a ) + (3 × 2 ) = 12a + 6


8 0
2 years ago
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Y = 3(x+ 4)^2+ 4 plz find the vertex and whether the graph has a minimum or maximum point
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Answer:

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Step-by-step explanation:

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2 years ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
2 years ago
Yo what's 0.994 rounded to the nearest tenth
krek1111 [17]

Answer:To round 0.994 to the nearest tenth consider the hundredths’ value of 0.994, which is 9 and equal or more than 5. Therefore, the tenths value of 0.994 increases by 1 to 0.

0.994 rounded to the nearest tenth = 1.0

Step-by-step explanation:

3 0
3 years ago
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Pls help with these. Ty. :)
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Answer:

I think the most common way of being a parent has to do something about the way it works for me in my career as.!!

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