Let x be ml of 5% soln.
let 500-x be ml of 25% soln.
.
x*.05=.05x
(500-x)*.25=125-.25x
500*.20=100
.
.05x+125-.25x=100
-.2x=-25
x=-25/-.2
x=125 ml of 5% soln.
500-x=375 ml of 25% soln.
.
Check:
125*.05= 6.25
375*.25=93.75
---------------
========100
Answer:
2
Step-by-step explanation:
Answer:
y=6/5x-8
Step-by-step explanation:
Hi there!
We want to find the equation of the line that passes through (5, -2) and has the slope of 6/5
We can write the equation of the line in slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept.
Since we are already given the slope of the line, we can immediately plug it into the equation:
y=6/5x+b
Now we need to find b
Since the equation passes through the point (5, -2), we can use it to solve for b
Substitute 5 as x and -2 as y:
-2=6/5(5)+b
Multiply
-2=6+b
Subtract 6 from both sides
-8=b
Substitute -8 as b.
y=6/5x-8
Hope this helps!
Answer:
so a perpendicular line's slope will be the opposite reciprocal
in 4r-10y=40 the slope of this line is 4/10(-a/b). So the slope of the perpendicular line would be -10/4 (-5/2) hope this helps!
I am probably wrong but with the math I do I got 35
