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zzz [600]
3 years ago
12

If you don't know the answer please don't "act" smart and put random things like links...

Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0

It's physics, right?

A. will have box 2.

B. will have box 1

C. will have box 3

rosijanka [135]3 years ago
6 0

Answer:

<u>Part A will be the 2nd line</u>

<u>Part B will be the 1st line</u>

<u>Part C will be the 5th line</u>

<u>*note* I don't know if these lines move as you move them so I getting these answers as if they do not move.</u>

Step-by-step explanation:

Let's start with part A.

It says he rides quickly. This means that as the distance increases, the time will increase slower.

So we are looking for a steep line. The steepest lines are line 2, 3 and 4

We know it can not be the 4th line because these line shows that time is no longer moving, just the distance.

Since it is impossible to freeze time, line 4 does not make any sense. So let's look at line 2 and 3

This can be confusing because it says down hill. So you may think it is line 3. When Cole goes down the hill, he is getting further from home. This means the line has to go up.

So that means part A has to be line 2.

Now let's start with part B

When graphing distance and time, if someone stops, their line stops moving in one direction too.

If you stop moving, you are not gaining any distance but time still moves.

This means we are looking for a line that moves in only 1 direction. These lines are lines 1 and 4.

On line 1, only time is moving

On line 4, only distance is moving

So like I said before, it is impossible to move while time is not moving. So line 4 makes no sense again. Leaving us with line 1.

So part B is line 1

Now we will do part C

It says that Cole rides slowly.

This means the line will not be steep. He is also still moving so it can not be line 1.

So we have line 5 and 6.

Since he is still moving away from the house, the line has to go up in distance and time. So this eliminates line 6

This leaves us with line 5

So the answer to part C is line 5

Hope this helps and have a great day!

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What is the solution to the system of equations? {x+2y=10y=12x+3
Marianna [84]

The solution to given system of equations are (x,y) = (\frac{4}{25} , \frac{123}{25})

<em><u>Solution:</u></em>

Given that we have to find solution to the system of equations

<em><u>Given equations are:</u></em>

x + 2y = 10  ------ eqn 1

y = 12x + 3 ------ eqn 2

We can solve the above equations by substitution method

<em><u>Substitute eqn 2 in eqn 1</u></em>

x + 2(12x + 3) = 10

x + 24x + 6 = 10

25x = 10 - 6

25x = 4

x = \frac{4}{25}

<em><u>Substitute the above value of x in eqn 2</u></em>

y = 12(\frac{4}{25}) + 3\\\\y = \frac{48}{25} + 3\\\\y = \frac{48+75}{25}\\\\y = \frac{123}{25}

Thus the solution to given system of equations are (x,y) = (\frac{4}{25} , \frac{123}{25})

5 0
4 years ago
A drawing has a scale 1/4 in: 12ft. How long is 8ft?
allochka39001 [22]
If you use a proportion, you'll get:

\frac{0.25}{12} =  \frac{x}{8}

Then, you use cross products:

12x=0.25(8) \\ 12x=2

Then, you algebraically solve x:

12x=2 \\ \frac{12x}{12} =  \frac{2}{12}  \\ x= \frac{5}{3}

The answer is 5/3 inches , or 1 5/13 inches, or 1.6 repeating.
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4 years ago
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zubka84 [21]
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7 0
3 years ago
Read 2 more answers
A random sample has been selected from a population. The point estimate = 78.65 and margin of error E = 8.24 for a 90% confidenc
fiasKO [112]

Answer:

90% confidence interval: (70.41,86.89)

Step-by-step explanation:

We are given the following in the question:

Point estimate = 78.65

Margin of error, E = 8.24

Confidence level = 90%

Significance level = 10%

Formula:

\text{Point estimate} \pm \text{Margin of error}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.10} = \pm 1.64

78.65 \pm 8.24 = (70.41,86.89)

(70.41,86.89) is the required 90% confidence interval.

5 0
4 years ago
If xsquared+ysquared=57 , xy=3 . find the value of 3(x+y)squared
shepuryov [24]

Answer:

189

Step-by-step explanation:

If you mean this, my answer is 3x63= 189

{x}^{2}  +  {y}^{2}  = 57 \\ xy = 3

{x}^{2}  +  {y}^{2}  + 2xy = 57 + 2 \times 3

{(x + y)}^{2}  = 63

3 {(x + y)}^{2}  = 3 \times 63 = 189

6 0
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