We have been given an expression $\left(\dfrac {6}{17}\right)^{9x}$ . We are asked to find the value of A when rewrite our given expression as $A^{x}$ .

To solve our given problem, we will use exponent properties.

Using exponent property $a^{mn}=(a^m)^n$ , we can rewrite our given expression as:

$\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}$

Now, we will compare our expression with $A^{x}$ .

Upon comparing $\left(\left(\dfrac {6}{17}\right)^9\right)^{x}$ with $A^{x}$ , we can see that $A=\left(\dfrac {6}{17}\right)^9$ .

Therefore, the value of A is $\left(\dfrac {6}{17}\right)^9$ .

We can further simplify $\left(\dfrac {6}{17}\right)^9$ as:

$\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}$

6 0

3 years ago

What is the ratio of ounces of<br> peanuts to ounces of almonds?

MAXImum [283]

Answer:

In what?

Step-by-step explanation:

7 0

3 years ago