Answer:
Supplimentry
Step-by-step explanation:
lx-1 l ≤ 13
There are 2 solutions:
x-1 ≤ 13
and
x-1 ≥ -13
Solve each one
x-1 ≤ 13
add 1 to both sides of the equation
x-1+1≤ 13+1
x ≤ 14
x-1 ≥ -13
Add 1 to both sides:
x-1+1 ≥-13+1
x ≥ -12
-12 ≤ x ≤ 14
Answer:
IQR: is the length of the middle 50% of that interval of space
Step-by-step explanation:
In order to find IQR, subtract the third interquartile range - the first interquartile range
I think the answer is y-11=0.
I am confused because there is no slope given so what I did is I just replaced y with its vakue that was given and determoned as to what equation is true.
So,
y-11=0
11-11=0
