Question

Anyone know the answer?

Answer 1

Step-by-step explanation:

${9}^{ \frac{ - 1}{2} } \\ {3}^{2 \times - \frac{1}{2} } \\ {3}^{ - 1} \\ \frac{1}{3}$

Now for another

${27}^{ \frac{ - 2}{3} } \\ {3}^{3 \times \frac{ - 2}{3} } \\ {3}^{ - 2} \\ \frac{1}{9}$

Hope it will help :)❤