All categories

3 years ago

Write an equivalent expression of -2x+7

Mathematics

2 answers:

Sindrei [870]3 years ago

7 0

-x-x+7 would be equivalent

Rzqust [24]3 years ago

4 0

Answer:

7 - 2x

Step-by-step explanation:

You might be interested in

HELPPPPPPPPPPPP

vlabodo [156]

Answer:

25cm

Step-by-step explanation:

one the possibility 36 - 11 =25 the answer is 25

8 0

2 years ago

I need to find the area of the figure

Ronch [10]

The area of the figure is 161

3 0

3 years ago

Read 2 more answers

3(x +2)-9x+5<br> What is the answer

Alika [10]

Answer:

-6x+11

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The standard normal curve shown below is a probability density curve for a

Step2247 [10]

Answer:

0.6825

Explanation:

I'm not fully sure about how to do this, but I believe it might have to do with

the approx. amount of shade, but please take this explanation with a grain of salt as I'm not 100% certain. I am certain about the answer however.

8 0

2 years ago

An industry representative claims that 10 percent of all satellite dish owners subscribe to at least one premium movie channel.

Greeley [361]

Answer: 1) 0.6561 2) 0.0037

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x success in n trials is given by :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

, where p =Probability of getting success in each trial.

As per given , we have

The probability that any satellite dish owners subscribe to at least one premium movie channel. : p=0.10

Sample size : n= 4

Let x denotes the number of dish owners in the sample subscribes to at least one premium movie channel.

1) The probability that none of the dish owners in the sample subscribes to at least one premium movie channel = $P(X=0)=^4C_0(0.10)^0(1-0.10)^{4}$

$=(1)(0.90)^4=0.6561$

∴ The probability that none of the dish owners in the sample subscribes to at least one premium movie channel is 0.6561.

2) The probability that more than two dish owners in the sample subscribe to at least one premium movie channel.

= $P(X>2)=1-P(X\leq2)\\\\=1-[P(X=0)+P(X=1)+P(X=2)]\\\\= 1-[0.6561+^4C_1(0.10)^1(0.90)^{3}+^4C_2(0.10)^2(0.90)^{2}]\\\\=1-[0.6561+(4)(0.0729)+\dfrac{4!}{2!2!}(0.0081)]\\\\=1-[0.6561+0.2916+0.0486]\\\\=1-0.9963=0.0037$

∴ The probability that more than two dish owners in the sample subscribe to at least one premium movie channel is 0.0037.

8 0

3 years ago