All categories

3 years ago

Complete the following statement mentally.

Mathematics

1 answer:

Oliga [24]3 years ago

5 0

Answer:

The answer to your question is given below.

Step-by-step explanation:

Let the total number be U.

From the question given above, we were told that any number of B is 50% of the total number (i.e U).

Now, we shall determine the the total number (U) in terms of B.

50% of U = B

50/100 × U = B

50U / 100 = B

Cross multiply

50U = 100B

Divide both side by 50

U = 100B/50

U = 2B

Thus, the total number is 2B

Finally, we shall determine the answer to the question:

111 is 50% of ___

B = 111

Total number (U) = 2B

Total number (U) = 2 × 111

Total number (U) = 222

Therefore,

111 is 50% of 222

You might be interested in

Find P(A or B or C) for the given probabilities. P(A=0.38, P(B)=0.28, P(C)=0.11 P(A and B)= 0.11, P(A and C)=0.02, P(B and C)=0.

kozerog [31]

Attached is a ven diagram which may be helpful for this problem.

Each number is a probability. The sum of all the numbers is P(A or B or C).

To find these numbers, start in the middle and work your way out.

The middle is P(A and B and C), which is 1. Then simply subtract this from each of the larger intersections.

Finally the parts not in an intersection. Only in A not B not C. You just subtract the numbers in A from P(A). ---> 38 - 10 -1 - 1 = 26

Add them up and you get 58.

P(A or B or C) = 0.58

4 0

3 years ago

Read 2 more answers

G let x be an exponentially distributed random variable with parameter λ = 1 / 2 . determine the probability distribution functi

Tema [17]

$X$ has CDF

$F_X(x)=\mathbb P(X\le x)=\begin{cases}1-e^{-\lambda x/2}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

The CDF of $Y$ is then

$F_Y(y)=\mathbb P(Y\le y)=\mathbb P(X^2\le y)=\mathbb P(X\le\sqrt y)=F_X(\sqrt y)$
$\implies F_Y(y)=\begin{cases}1-e^{-\lambda\sqrt y/2}&\text{for }y\ge0\\0&\text{otherwise}\end{cases}$
$\implies F_Y(y)=\begin{cases}1-e^{-(y/(4/\lambda^2))^{1/2}}&\text{for }y\ge0\\0&\text{otherwise}\end{cases}$

which is the CDF of a Weibull distribution with shape parameter $\dfrac4{\lambda^2}$ and scale parameter $\dfrac12$ .

4 0

3 years ago

2 less than a number times 6

Alex17521 [72]

Answer: 6x- 2

Explanation: 2 less means (- 2) a number times 6 can be written as 6x

8 0

4 years ago

Read the passage from "The Walrus and the Carpenter."

Greeley [361]

Answer: i think the awnser is c

Step-by-step explanation: hope it helps

8 0

3 years ago

HELLO? HELLO? ANYONE THERE TO ANSWER

Svetach [21]

Answer:

-2u + w ⇒ answer B

Step-by-step explanation:

* To solve this problem you must find the result from the graph

- The ray move from the origin 6 units to the left and then 1 unit up

∴ The result is <-6 , 1>

* Now lets check which answer give the same result

∵ u = <5 , -5> , v = <1 , -4> , w = <4 , -9>

# Answer A: w - 2v

∵ w = <4 , -9>

- Find 2v by multiply v by 2

∵ 2v = 2<1 , -4> = <2 , -8>

- Subtract 2v from w

∴ w - 2v = <4 , -9> - <2 , -8> = <(4 - 2) , (-9 - -8)> = <2 , -1> ≠ <-6 , 1>

# Answer B: -2u + w

∵ u = <5 , -5>

- Find -2u by multiply u by -2

∵ -2u = -2<5 , -5> = <-10 , 10>

- Add -2u and w

∵ w = <4 , -9>

∴ -2u + w = <-10 , 10> + <4 , -9> = <(-10 + 4) , (10 + -9)> = <-6 , 1> = <-6 , 1>

∴ The answer is B

8 0

3 years ago

Read 2 more answers