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3 years ago

2-V18 - 2/12 + 2V18 =

Mathematics

2 answers:

Zepler [3.9K]3 years ago

7 0

Answer:

D=12/2

Step-by-step explanation:

Let's simplify step-by-step.

2−v18− 2 /12 +2v18

=2+−v18+ −1 /6 +2v18

(−v18+2v18)+(2+ −1 /6 )

v18+ 11 /6

D=Correcto

2-V^{18}-2/12+2V^{18}=12/2

v=1.082512

umka2103 [35]3 years ago

7 0

I don’t have a clue

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Add.7 1/6 + 3 2/6 Express your answer in simplest form. ____ A. 10 1/2 B10 3/12 C. 10 3/6 D.11 3/12

goblinko [34]

The answer is a. hope that helped

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3 years ago

Given that x is a hypergeometric random variable with Nequals10, nequals4, and requals6, complete parts a through d. a. Compu

sergey [27]

Answer:

a. 0.114

b. 0.005

c. 0.381

d. 0.00

Step-by-step explanation:

If x follows a hypergeometric distribution, the probability that x is equal to k is calculated as:

$P(x=k)=\frac{(rCk)*((N-r)C(n-k))}{NCn}$

Where k≤r and n-k≤N-r, Additionally:

$aCb=\frac{a!}{b!(a-b)!}$

So, replacing N by 10, n by 4 and r by 6, we get:

$P(x=k)=\frac{6Ck*((10-6)C(4-k))}{10C4}=\frac{6Ck*(4C(4-k))}{10C4}$

Then, the probability that x is equal to 1, P(x=1) is:

$P(x=1)=\frac{6C1*4C3}{10C4}=0.114$

The probability that x is equal to 0, P(x=0) is:

$P(x=0)=\frac{6C0*4C4}{10C4}=0.005$

The probability that x is equal to 3, P(x=3) is:

$P(x=3)=\frac{6C3*4C1}{10C4}=0.381$

Finally, in this case, x can take values from 0 to 4, so the probability that x is greater or equals to 5 is zero.

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3 years ago

You have a large jar that initially contains 30 red marbles and 20 blue marbles. We also have a large supply of extra marbles of

Dima020 [189]

Answer:

There is a 57.68% probability that this last marble is red.

There is a 20.78% probability that we actually drew the same marble all four times.

Step-by-step explanation:

Initially, there are 50 marbles, of which:

30 are red

20 are blue

Any time a red marble is drawn:

The marble is placed back, and another three red marbles are added

Any time a blue marble is drawn

The marble is placed back, and another five blue marbles are added.

The first three marbles can have the following combinations:

R - R - R

R - R - B

R - B - R

R - B - B

B - R - R

B - R - B

B - B - R

B - B - B

Now, for each case, we have to find the probability that the last marble is red. So

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8}$

$P_{1}$ is the probability that we go R - R - R - R

There are 50 marbles, of which 30 are red. So, the probability of the first marble sorted being red is $\frac{30}{50} = \frac{3}{5}$ .

Now the red marble is returned to the bag, and another 3 red marbles are added.

Now there are 53 marbles, of which 33 are red. So, when the first marble sorted is red, the probability that the second is also red is $\frac{33}{53}$

Again, the red marble is returned to the bag, and another 3 red marbles are added

Now there are 56 marbles, of which 36 are red. So, in this sequence, the probability of the third marble sorted being red is $\frac{36}{56}$

Again, the red marble sorted is returned, and another 3 are added.

Now there are 59 marbles, of which 39 are red. So, in this sequence, the probability of the fourth marble sorted being red is $\frac{39}{59}$ . So

$P_{1} = \frac{3}{5}*\frac{33}{53}*\frac{36}{56}*\frac{39}{59} = \frac{138996}{875560} = 0.1588$

$P_{2}$ is the probability that we go R - R - B - R

$P_{2} = \frac{3}{5}*\frac{33}{53}*\frac{20}{56}*\frac{36}{61} = \frac{71280}{905240} = 0.0788$

$P_{3}$ is the probability that we go R - B - R - R

$P_{3} = \frac{3}{5}*\frac{20}{53}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{937570} = 0.076$

$P_{4}$ is the probability that we go R - B - B - R

$P_{4} = \frac{3}{5}*\frac{20}{53}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{968310} = 0.0511$

$P_{5}$ is the probability that we go B - R - R - R

$P_{5} = \frac{2}{5}*\frac{30}{55}*\frac{33}{58}*\frac{36}{61} = \frac{71280}{972950} = 0.0733$

$P_{6}$ is the probability that we go B - R - B - R

$P_{6} = \frac{2}{5}*\frac{30}{55}*\frac{25}{58}*\frac{33}{63} = \frac{49500}{1004850} = 0.0493$

$P_{7}$ is the probability that we go B - B - R - R

$P_{7} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{33}{63} = \frac{825}{17325} = 0.0476$

$P_{8}$ is the probability that we go B - B - B - R

$P_{8} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{30}{65} = \frac{750}{17875} = 0.0419$

So, the probability that this last marble is red is:

$P = P_{1} + P_{2} + P_{3} + P_{4} + P_{5} + P_{6} + P_{7} + P_{8} = 0.1588 + 0.0788 + 0.076 + 0.0511 + 0.0733 + 0.0493 + 0.0476 + 0.0419 = 0.5768$

There is a 57.68% probability that this last marble is red.

What's the probability that we actually drew the same marble all four times?

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that we go R-R-R-R. It is the same $P_{1}$ from the previous item(the last marble being red). So $P_{1} = 0.1588$

$P_{2}$ is the probability that we go B-B-B-B. It is almost the same as $P_{8}$ in the previous exercise. The lone difference is that for the last marble we want it to be blue. There are 65 marbles, 35 of which are blue.

$P_{2} = \frac{2}{5}*\frac{25}{55}*\frac{1}{2}*\frac{35}{65} = \frac{875}{17875} = 0.0490$

$P = P_{1} + P_{2} = 0.1588 + 0.0490 = 0.2078$

There is a 20.78% probability that we actually drew the same marble all four times

3 0

3 years ago

Each Serving of pasta is 1/2 pound. Drag to correct equation to each amount to show how many 1/2 pound serving Can be made

nataly862011 [7]

Step-by-step explanation:

4 pounds is 4÷1=8

5 pounds is 5÷1=10

4 0

3 years ago

Tony and his three friends live in Albuquerque, New Mexico, but they all attend college in Boston, Massachusetts. Because they w

astra-53 [7]

Hello...

Tony and his three friends live in Albuquerque, New Mexico, but they all attend college in Boston, Massachusetts. Because they want to have a car at school this year, they are planning to drive Tony's car from Albuquerque to Boston at the beginning of the school year. Although they'll each pay for their own food during the road trip, the friends plan to split the costs for gas and hotels evenly between the four of them.

Estimate the total cost that each friend will have to pay for gas and hotels. Explain how you got your answer. Here are some figures that may help you out:

•Tony's car can travel 28 miles for each gallon of gas.

•The average fuel cost at the time of their trip is $3 per gallon.

•They plan to drive about 650 miles each day.

•They estimate the average cost of a hotel each night is $85.

•They will drive approximately 2,240 miles to get from Albuquerque to Boston.

Solution:

Cost of Gas:

2240 / 28 x 3 = $240

Cost of Lodging:

85 x floor2240 / 650 = $255

Cost of both: $240 +255 = $495.

The cost for a 1/4 share is $495/4 = $123.75.

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3 years ago