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2 years ago

Could someone please help with 5,6 is due right now!! Will get brainiest if helped now!! Thank you.

Mathematics

1 answer:

ipn [44]2 years ago

8 0

3. x: 180-99 = 81º (angles on a straight line equals 180)

y: 115-81 = 34º (exterior angle is sum of opposite interior angles)

4. y: 180-64 = 116 (angles on a straight line equals 180)

x: 126º

two steps

angles on straight line equals 180: 180-118 = 62º

exterior angle is sum of opposite interior angles: 62+64 = 126º

sorry if i misread any of the numbers, let me know if i did and i'll fix it

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How can you use transformations to solve problems?

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3 years ago

The altitude of a triangle is increasing at a rate of 1.5 1.5 centimeters/minute while the area of the triangle is increasing at

seraphim [82]

Answer:

The base reduces at 3.75cm/min

Step-by-step explanation:

Given

Let

$h \to altitude$

$b \to base$

$A \to Area$

So:

$\frac{dh}{dt} = 1.5cm/min$

$\frac{dA}{dt} = 1.5^2cm/min$

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$A = \frac{1}{2}bh$

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$88=\frac{1}{2} * b * 8$

$88 =b * 4$

Solve for b

$b = 88/4$

$b = 22$

We have:

$A = \frac{1}{2}bh$

Differentiate with respect to time

$\frac{dA}{dt} =\frac{1}{2}(h\frac{db}{dt} + b\frac{dh}{dt})$

Substitute the following values in the above equation

$\frac{dh}{dt} = 1.5cm/min$ $\frac{dA}{dt} = 1.5^2cm/min$ $b = 22$ $h = 8$

$1.5 = \frac{1}{2}(8 * \frac{db}{dt} + 22 * 1.5)$

Multiply both sides by 2

$3 = 8 * \frac{db}{dt} + 22 * 1.5$

$3 = 8 * \frac{db}{dt} + 33$

Collect like terms

$8 * \frac{db}{dt} = 3 -33$

$8 * \frac{db}{dt} = -30$

Divide both sides by 8

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3 years ago

For the function N(y)=-3y-7, evaluate N(1)

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Answer:

N(1) = -10

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

N(y) = -3y - 7

N(1) is y = 1

Step 2: Evaluate

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2 years ago

A smuggler leaves a private airfield at 06:00 flying at a heading of N40E at 200km/h. The plane is detected by radar at the poli

gtnhenbr [62]

Answer:

Direction of the police plane = N57.1E

Speed of the police airplane = 255 km/h

Step-by-step explanation:

The diagram of the situation described is presented in the attached image to this question.

Let the distance the police airplane has to travel to intercept the smuggler at 08:30 be x km

The police airplane moves at 06:30 and plans to intercept the smuggler at 08:30; thereby travelling for 2 hours.

By 08:30, the smuggler would have travelled for 2 hours 30 mins, that is, 2.5 hours, travelling at 200 km/h, that is a total distance of 500 km covered.

So, the paths form a triangle.

Using cosine rule, we can obtain the distance, x, that the police airplane has to travel to intercept the smuggler at 08:30.

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x² = 259,426.63858785

x = 509.34 km

We can obtain the direction, Φ, by finding the angle θ using some rule.

[(Sin 85°)/509.34] = [(Sin θ)/500]

Sin θ = (500 × sin 85°)/509.34 = 0.9779 = 77.94°

From the attached image,

Φ + θ = 90° + 45° = 135°

Φ = 135° - θ = 135° - 77.94° = 57.06° = 57.1°

Therefore,

Speed of police airplane = (distance)/(time) = (509.34/2) = 254.67 km/h = 255 km/h

Direction of the police plane = N57.1E

Hope this Helps!!!

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3 years ago