All categories

3 years ago

My sister needs help with this

Mathematics

1 answer:

Oliga [24]3 years ago

4 0

Sailing ships should be correct

You might be interested in

Students are measuring the mass of an object in Science class. The mass is 38 grams. Danielle measured the mass at 40 grams. Wha

Ad libitum [116K]

Answer:

5.26%

Step-by-step explanation:

Danielle measured the the mass at 40grams. ,Compared to 38 grams, there is a percentage increase.

Old Value = 38grams, New Value = 40grams

%Increase = 40-38/38 × 100%

%Increase = 5.26%

8 0

3 years ago

Which inequality would result in the shaded solution on the unit circle to the right?

snow_tiger [21]

Answer:

B tan(x)<1

Step-by-step explanation:

edgenuity 2020

6 0

4 years ago

Simplify. (x 3) 4 • x -3 x -36 x 9 x 4 x -21

Levart [38]

Answer:

-1295x -21

Step-by-step explanation:

srry if it wrong

4 0

3 years ago

Read 2 more answers

In the equation y = 6.7x, what is the constant of proportionality

devlian [24]

The constant in an equation would be the number multiplied to x,

In the equation y - 6.7x, the constant would be 6.7

4 0

3 years ago

A calculator is required to obtain the final answer on this question. A solid metal sphere at room temperature 20oC is dropped i

yKpoI14uk [10]

Answer:

T = 47.1875°C

Step-by-step explanation:

Given:

Surrounding temp, Ts = 100°C

Initial Temperature ,T0= 20°C

Increase in temperature = 15°C

Final temperature, T = 20 + 15 = 35°C

Time, t = 9 seconds

Let's take Newton's law of cooling:

$T - Ts = (T_0 - Ts)e^k^t$

We'll solve for k

$35 - 100 = (20 - 100)e^9^k$

$-65 = (-80)e^9^k$

Divide both sides by -5

$13 = (16)e^9^k$

$9k = ln (\frac{13}{16})$

$k = \frac{1}{9} ln (\frac{13}{16})$

$k = -0.02307104053$

Let's now find the temperature of the ball after 18 seconds in boiling water.

Use the Newton's equation again:

$T - Ts = (T_0 - Ts)e^k^t$

$T - 100 = (20 - 100)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100 = (-80)e^-0.0^2^3^0^7^1^0^4^0^5^3^*^1^8$

$T - 100= -52.8125$

$T = 100 - 52.8125$

T = 47.1875°C

Temperature of the ball after 18 seconds in boiling water is 47.1875°C

5 0

4 years ago