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SSSSS [86.1K]
3 years ago
13

Solve using the quadratic formula 2x^2 + 7x - 15 = 0

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

1.5 or -5

Step-by-step explanation:

2x²+7x-15=0

Divide by 2:

x²+7x/2-15/2=0

x=-7/2/2 ± √49/4(4)+15/2

  =-7/4 ± √49/16+120/16

  =-7/4± √169/16=-7/4 ±13/4

  =6/4 or -20/4

   =1.5 or -5

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On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and
Otrada [13]

Answer:

P = 4\sqrt{13}

Step-by-step explanation:

Given

W = (7, 2)

X = (5, -1)

Y = (3, 2)

Z =(5, 5)

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

So, we have:

WX = \sqrt{(5- 7)^2 + (-1 - 2)^2

WX = \sqrt{13}

XY = \sqrt{(3-5)^2 + (2--1)^2}

XY = \sqrt{13}

YZ = \sqrt{(5-3)^2 + (5-2)^2}

YZ = \sqrt{13}

ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}

ZW = \sqrt{13}

The perimeter is:

P = WX + XY + YZ + ZW

P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}

P = 4\sqrt{13}

5 0
3 years ago
Read 2 more answers
HELP ASAP PLZ 15 points!<br> ............
Allisa [31]

Well I would say A because it went from 8 to 38 which is plus ten.

7 0
3 years ago
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What is the slope of the line that passes through (2, 3) and has a y-intercept of -1?
sashaice [31]
I believe that the slope would be 4/2 or 2, but i wouldn’t take my word for it
7 0
3 years ago
Justify why a / b x b / c x c /d x d / e is equal to a /e when B C D and E are not zero
Maru [420]

a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

 

PROVE

 a/b * b/c * c/d * d/e

= (a/b *b/c) * (c/d * d/e)

= ab/bc * (c/d * d/e)

= a/c * (c/d * d/e)

= a/c * (cd/de)

= a/c * c/e

= ac/ce

= a/e

 

Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

7 0
4 years ago
The midpoint M and one endpoint of JK are given. Find the coordinates of the other endpoint. J(7,2) and M(1,-2)
djverab [1.8K]

Step-by-step explanation:

Xj + Xk/2 = Xm

7 + Xk/2 = 1

to get rid of the bracket, multiply all two sides by the denominator.

2(7 + Xk/2) = 1(2)

7 + Xk = 2

Xk = 2 - 7

Xk = -5

Yj + Yk/2 = Ym

2 + Yk/2 = -2

to get rid of the bracket, multiply all two sides by the denominator.

2(2 + Yk/2) = -2(2)

2 + Yk = -4

Yk = -4 - 2

Yk = -6

Therefore the coordinates of point K is (-5,-6)

3 0
3 years ago
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