What is the equation of the line perpendicular to y=-1/5x -2 and contains the point (2, -10)?
2 answers:
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Answer:
67.38°
Step-by-step explanation:
The diagonals of a rhombus intersect at their midpoints and make a right angle. They also divide the angles of the rhombus in two equal angles.
So, to find the acute angle of the rhombus, we can use the tangent relation of half this angle in the small triangle made when drawing the diagonals:
tan(angle/2) = 4 / 6
tan(angle/2) = 0.666
angle/2 = 33.69
angle = 67.38°
So the acute angle of the rhombus is 67.38 degrees.
Please check the image attached for better comprehension.
