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Nady [450]
3 years ago
14

Find the value of x.

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
X=4. Do 9x-8=28 bc they are the same length. Add 8 to the other side and u should get 36. Divide both sides by nine to get x by itself and u should have 4 as ur answer.
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15 points for someone who can answer & explain this to me thanks
iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

\frac{9}{a^2+9a+20} , \frac{7a}{a^2+11a+28}

Factor the denominators of both fractions

\frac{9}{(a+4)(a+5)} , \frac{7a}{(a+4)(a+7)}

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

\frac{9(a+7)}{(a+4)(a+5)(a+7)} , \frac{7a(a+5)}{(a+4)(a+5)(a+7)} , then

\frac{9a+63}{(a+4)(a+5)(a+7)} , \frac{7a^2+35a}{(a+4)(a+5)(a+7)}

8 0
3 years ago
Ida is cutting a 11/12 foot wooden board into 3/16 foot sections to do some detail work on a model she is building. How many who
zlopas [31]
You have to give them the same denominator so multiply 11/12 by 4 and 3/16 by 3. giving you 44/48 and 9/48. then divied 44 by 9 giving you 4.8888
there for there are 4 whole 3/16 sections of the 11/12 board
3 0
4 years ago
Read 2 more answers
State if the two triangles are congruent. If they are, state how you know.
Gwar [14]

Answer:

The triangles can be congruent.

Step-by-step explanation:

They are congruent if proven by SSS: 2 sides are clearly stated that they are congruent due to the marks they have.

The last side can be congruent if the diagonals are congruent in length by proving.

They can also be congeuent due to SAS because there is gonna be alternate interior angles due to the transversal.

4 0
3 years ago
Couldn't write it out so i took a pic of it
olasank [31]

Answer:

4th is the answer

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Find the area of ABC with vertices A(3,-6), B(5,-6), and C(7,–9).
stellarik [79]

Area of a triangle ABC with the given vertices is 3 square units.

Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).

<h3>What is the area of triangle formula in coordinate geometry?</h3>

In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.

Area of a triangle = \frac{1}{2} ( |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|)

Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)

Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)

= 1/2 (|3(3)+5(-3)+7(0)|)

= 1/2 (|(9-15)|)

= 1/2 × 6

= 3 square units

Therefore, area of a triangle ABC with the given vertices is 3 square units.

To learn more about the area of a area of triangle with vertices visit:

brainly.com/question/26633662.

#SPJ1

7 0
2 years ago
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