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3 years ago

Subtract. 8 4/5−5 1/10 options 3 7/10 3 3/10 3 5/5 3 3/5

Mathematics

1 answer:

skad [1K]3 years ago

8 0

Answer:

3 7/10

Step-by-step explanation:

are u sure this is highschool cuz this is too easy and im in middle school :/

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Select the correct answer. The elimination method is ideal for solving this system of equations. By which number must you multip

Reptile [31]

Answer:

Step-by-step explanation:

Multiply the second equation by 2. The solution is x = 15, y = 9.

7 0

3 years ago

Read 2 more answers

|2x - 3| = 15 solve for x.

denis23 [38]

Answer:

X=9

Step-by-step explanation:

Get the variables on one side by adding 3 to both sides making it

2x=18 divide it then by 2 getting X

3 0

3 years ago

ScrapBook,you cut a picture into a right triangle for your scrapbook, the lengths of the lago of the triangle are 4 inches and 6

AveGali [126]

Answer:

hypotenuse is not a rational number

Step-by-step explanation:

In a Right angled triangle , if a, b are the sides and h be the hypotenuse then relationship between them is given by

$h^{2}$ = $a^{2}$ + $b^{2}$

Here,

a= 4 in. [Given]

b = 6 in. [Given]

Thus ,

$h^{2}$ = $4^{2}$ + $6^{2}$

$h^{2}$ = 16 + 36

$h^{2}$ = 52.

h = $\sqrt{52}$ = 7.21110255......

Clearly, h is not a rational number

6 0

3 years ago

Find an equation of the circle that satisfies the given conditions. (Use the variables x and y.)

prohojiy [21]

Answer:

$x^2 + y^2 = 52$

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, $(x_1,y_1)$ and $(x_2,y_2)$ . The distance between them is given by:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Equation of a circle:

The equation of a circle with center $(x_0,y_0)$ and radius r has the following format:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Center at the origin;

This means that $x_0 = 0, y_0 = 0$

$(x - x_0)^2 + (y - y_0)^2 = r^2$

$(x - 0)^2 + (y - 0)^2 = r^2$

$x^2 + y^2 = r^2$

Passes through (4, 6)

The radius is the distance from this point to the center. So

$r = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r = \sqrt{(4-0)^2+(6-0)^2}$

$r = \sqrt{16+36}$

$r = \sqrt{52}$

$r^2 = 52$

Then

$x^2 + y^2 = r^2$

$x^2 + y^2 = 52$

8 0

3 years ago

X= A. 115.5 B. 137 C. 180

zhuklara [117]

Answer:

The correct answer option is C. 180

Step-by-step explanation:

We are given a figure of a circle with two known angles measuring 137 degrees and 94 degrees and we are to find the value of x.

Finding x:

$137 = \frac{1}{2} (\angle x + 94)$

$137 = \frac{1}{2} \angle x + 47$

$\frac{1}{2} \angle x = 137 - 47$

$\frac{1}{2} \angle x = 90
$

$\angle x = 90 \times 2&# 1 0$

x = 180

5 0

3 years ago