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Juli2301 [7.4K]
3 years ago
15

Place the Circle on the

Mathematics
1 answer:
lesya [120]3 years ago
5 0
Y intercept: when x = 0
(0, y)
On the graph it is (0,-5)
Solution: y intercept is (0,-5)
You might be interested in
I'm a little bit confused about how to approach this can someone help?
Taya2010 [7]

Answer:

4

Step-by-step explanation:

ΔABC is congruent with ΔDEF.  That means the corresponding sides are congruent.

Look at the order of the letters.  EF are the last two letters of ΔDEF.  So this corresponds with the last two letters of ΔABC.  Therefore, EF ≅ BC.

EF ≅ BC

x² + 8x = 48

x² + 8x − 48 = 0

(x + 12) (x − 4) = 0

x = -12 or 4

Since x can't be negative, x = 4.

5 0
3 years ago
Anybody help me? please
liq [111]

Answer:

0 because we can't have Repetitious x in function.

6 0
4 years ago
Plz help. 3y + 6 = -2x
Galina-37 [17]
Answer: 2x+3y = -6

Good luck !
7 0
3 years ago
Read 2 more answers
In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo
Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

P(B) = 0.6

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

P(A/B) = x

P(A) is the probability that the participant dies:

P(A) = P_{1} + P_{2} + P_{3}

P_{1} is the probability that a heavy smoker is selected and that he dies. So:

P_{1} = 0.15*5x = 0.75x

P_{2} is the probability that a light smoker is selected and that he dies. So:

P_{2} = 0.25*3x = 0.75x

P_{3} is the probability that a non-smoker is selected and that he dies. So:

P_{3} = 0.60*x = 0.60x

The probability that a participant dies is:

P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x

The probability of the participant being a non-smoker, given that he died, is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0
3 years ago
What is the answer to this please help
Elis [28]

Answer:

use calculater please it will not take long

4 0
3 years ago
Read 2 more answers
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