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Juli2301 [7.4K]
3 years ago
15

Place the Circle on the

Mathematics
1 answer:
lesya [120]3 years ago
5 0
Y intercept: when x = 0
(0, y)
On the graph it is (0,-5)
Solution: y intercept is (0,-5)
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How to solve for j -10=║j-7║
Aleksandr [31]

Answer:

No solutions.

Step-by-step explanation:

-10 = 7

No solutions

6 0
3 years ago
No clue what I am doing
Lesechka [4]

Answer:

1. 1=18°, 2=90°

2. 1=85°

3. 1=97°

4. 2=83°

5. 3=49°

6. 1=94°

7. 4=45°

8. 3=65°

9. 2=79°

10. 5=73°

11. 6=147°

12. 1=26°

13. 2=32°

Step-by-step explanation:

1. all angles of a triangle equal 180. 2 is 90 degrees because you can look across to find the symbol. Then you subtract 180 by 72 and 90 to get 18.

2. do the same thing as last time, 180 minus 40 and 55.

3. In order to figure this out, you need to have the angle 2. One you have 83, angles like this, together will add up to 360 if you put 2 of them together. 83×2=166. 360-166=194. 194/2=97.

4. To figure this out, you find the angle across from it because those are always the same. Follow the same process to subtract 39 and 58 from 180 to get 83.

5.Now that you have the angle 2 you can figure this one out as well, again, follow the process of subtracting the two opposite angles from 180 to get 49.

(This is taking really long to explain so if you have questions just ask.)

3 0
3 years ago
Find an equation of the plane. The plane that passes through the line of intersection of the planes x − z = 3 and y + 2z = 3 and
IgorLugansk [536]

Answer:

x-y-3=0

Step-by-step explanation:

Choose two common points on the line of intersection of the planes x − z = 3 and y + 2z = 3:

  • 1st point: if x=0, then z=-3 and y=3-2z=3+6=9, so the 1st point is (0,-3,9);
  • 2nd point: if x=3, then z=0 and y=3-2z=3-0=3, so the 2nd point is (3,0,3).

The perpendicular plane to the plane x+y-4z=6 is parallel to the vector with coordinates (1,1,-4) (normal vector of the given plane).

Hence, the equation of needed plane is

\left\|\begin{array}{ccc}x-0&y-(-3)&z-9\\3-0&0-(-3)&3-9\\1&1&-4\end{array}\right\|=0\Rightarrow \left\|\begin{array}{ccc}x&y+3&z-9\\3&3&-6\\1&1&-4\end{array}\right\|=0

Thus,

\left\|\begin{array}{ccc}x&y+3&z-9\\3&3&-6\\1&1&-4\end{array}\right\|=0\Rightarrow \\\\-12x-6(y+3)+3(z-9)-3(z-9)+6x+12(y+3)=0\\ \\-6x+6(y+3)=0\\ \\-x+y+3=0\\ \\x-y-3=0

4 0
4 years ago
Which of the following is equivalent to 5−1?
Troyanec [42]

Answer:

what r the options

Step-by-step explanation:

5 0
3 years ago
suppose the company's cost per 1 gallon is $2.70 what is the markup if they sell each gallon at $3.20 then what is the markup if
lukranit [14]

Answer:

A= 50cents markup B=80 cents markup

Step-by-step explanation:

U just subtract the markup by 270 then bam

7 0
3 years ago
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